Answer:
I think it is the forth one
How much power is needed to push a 95 kg chest at 0.67 m/s along a horizontal floor where the coefficient of friction is 0.77?
1 answer:
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Answer:
LED bulb = 0.145 A
Incandescent bulb = 0.909 A
CFL bulb = 0.218 A
Explanation:
Given:
Power rating of LED bulb (P₁) = 16 W
Power rating of incandescent bulb (P₂) = 100 W
Power rating of CFL bulb (P₃) = 24 W
Terminal voltage across the circuit (V) = 110 V
We know that, power is related to terminal voltage and current drawn as:
Express this in terms of 'I'. This gives,
Now, calculate the current drawn in each bulb using their respective values.
For LED bulb,
So, current drawn is given as:
For incandescent bulb,
So, current drawn is given as:
For CFL bulb,
So, current drawn is given as:
Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.
Answer:
The frequency of the oscillation is 2.45 Hz.
Explanation:
Given;
mass of the spring, m = 0.5 kg
total mechanical energy of the spring, E = 12 J
Determine the spring constant, k as follows;
E = ¹/₂kA²
kA² = 2E
k = (2E) / (A²)
k = (2 x 12) / (0.45²)
k = 118.519 N/m
Determine the angular frequency, ω;
Determine the frequency of the oscillation;
ω = 2πf
f = (ω) / (2π)
f = (15.396) / (2π)
f = 2.45 Hz
Therefore, the frequency of the oscillation is 2.45 Hz.