1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aleksklad [387]
4 years ago
15

Diffusion occurs faster in gases than in liquids because _____.

Physics
2 answers:
jolli1 [7]4 years ago
5 0
The correct answer to go in the blank would be A) The particles are moving faster.
My name is Ann [436]4 years ago
3 0

Answer:

the particles are moving faster

Explanation:

As we know that diffusion means the rate of escape of gas from small opening.

So here the diffusion rate is basically related to the speed of gas molecules to escape out of the closed container.

So here rate of diffusion is given as

Rate = \sqrt{\frac{P}{\rho}}

so it depends on pressure of gas and density of gas.

Also we know that gas molecules are loosely bounded to each other as we compare the bonding between molecules of liquid.

So here we will say that correct answer is

the particles are moving faster

You might be interested in
A car drives on a circular road of radius R. The distance driven by the car is given by = + [where a and b are constants, and t
pishuonlain [190]

Answer:

The question is incomplete, the complete question is "A car drives on a circular road of radius R. The distance driven by the car is given by d(t)= at^3+bt [where a and b are constants, and t in seconds will give d in meters]. In terms of a, b, and R, and when t = 3 seconds, find an expression for the magnitudes of (i) the tangential acceleration aTAN, and (ii) the radial acceleration aRAD3"

answers:

a.18a m/s^{2}

b. a_{rad}=\frac{(27a +b)^{2}}{R}

Explanation:

First let state the mathematical expression for the tangential acceleration and the radial acceleration.

a. tangential acceleration is express as

a_{tan}=\frac{d|v|}{dt} \\

since the distance is expressed as

d=at^{3}+bt

the derivative is the velocity, hence

V(t)=\frac{dd(t)}{dt}\\V(t)=3at^{2}+b\\

hence when we take the drivative of the velocity we arrive at

a_{tan}=\frac{dv(t)}{dt}\\ a_{tan}=6at\\t=3 \\we have \\a_{tan}=18a m/s^2

b. the expression for the radial acceleration is expressed as

a_{rad}=\frac{v^{2}}{r}\\a_{rad}=\frac{(3at^{2} +b)^{2}}{R}\\t=3\\a_{rad}=\frac{(27a +b)^{2}}{R}

4 0
3 years ago
How does the thermosphere,(the outer most layer) help earth?
Neko [114]
The THERMOSPHERE is the layer of the Earth's Atmosphere directly above the Mesosphere and directly below the Exophere.(I know its not much but,I hope it helps you)
7 0
3 years ago
What statement is true? (more than 1 answer)
Lisa [10]
Thes are all correct :<span>2.Scientists observe natural events occurring around them. They question these observations and investigate them.

3.All scientists follow one scientific method of investigation

4.If a hypothesis is not verified by the results from the scientific method, scientists may either redo the process or create a new hypothesis.</span>
7 0
3 years ago
A concrete piling of 50 kg is suspended from a steel wire of diameter 1.0 mm and length 11.2 m. How much will the wire stretch?
pentagon [3]

Explanation:

It is given that,

Mass of concrete pilling, m = 50 kg

Diameter of wire, d = 1 mm

Radius of wire, r = 0.0005 m

Length of wire, L = 11.2

Young modulus of steel, Y=20\times 10^{10}\ N/m^2

The young modulus of a wire is given by :

Y=\dfrac{\dfrac{F}{A}}{\dfrac{\Delta L}{L}}

Y=\dfrac{F.L}{A\Delta L}

\Delta L=\dfrac{F.L}{A.Y}

\Delta L=\dfrac{50\ kg\times 9.8\ m/s^2\times 11.2\ m}{\pi (0.0005\ m)^2\times 20\times 10^{10}\ N/m^2}

\Delta L=0.034\ m

So, the wire will stretch 0.034 meters. Hence, this is the required solution.

8 0
4 years ago
Jet aircraft maintenance crews are required to wear protective earplugs. Members of a particular crew wear earplugs that reduce
Taya2010 [7]

Answer:

So the sound intensity level they would experience without the earplugs is 110.32dB.

Explanation:

Given data

Sound intensity by factor =215

Sound intensity level =87 dB

To find

Sound intensity level they would experience without the earplugs

Solution

First we need to find the new sound intensity level

So

I_{n}=215(10^{\frac{87}{10} } )\\I_{n}=1.08*10^{11})

The dB can be calculated as:

dB=10log(I_{n})\\

Substitute the given values

dB=10log(1.08*10^{11})\\dB=110.32dB

So the sound intensity level they would experience without the earplugs is 110.32dB.

7 0
3 years ago
Other questions:
  • How many milliliters are in 3.65L
    14·2 answers
  • Name the 4 classes of marcolecules and give a funtion for each
    6·1 answer
  • A rubber ball with a mass of 0.30 kg is dropped onto a steel plate. The ball's velocity just before impact is 4.5 m/s and just a
    7·1 answer
  • Which are characteristics of the speed of light? Check all that apply.
    5·2 answers
  • A technician A says that a voltmeter can be used to monitor the output signal of an optical sensor. Technician B says that optic
    5·1 answer
  • A 60 kg skateboarder accelerates themselves at 1.5m/s2. How much force was required to do this?
    10·1 answer
  • PLEASE HELP.
    11·1 answer
  • How Many displacement vectors shown in the figure above have horizontal components
    9·1 answer
  • <img src="https://tex.z-dn.net/?f=%20%5Csf%20%7B%20%5Cfcolorbox%7Bgreen%7D%7Bg%7D%7B%20What%20are%20impulses%3F%7D%7D%20" id="Te
    11·1 answer
  • Habiba and selehadin have measured the voltage across a resistor to be 5.26V and the current flowing through in to be 0.41A they
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!