Answer:
after 2 seconds its velocity is -20 m/s. after 3 seconds its velocity is -30 m/s. after 10 seconds its velocity is -100 m/s.
Explanation:
This is my answer.
Answer:
The formula is a = F m so in this case a = 5 10 = 0.5 m s 2
Explanation:
The equation to be used here is the trajectory of a projectile as written below:
y = xtanθ +/- gx²/2v²(cosθ)²
where
y is the vertical distance
x is the horizontal distance
θ is the angle of trajectory or launch angle
g is 9.81 m/s²
v is the initial velcity
Since the angle is below horizontal, let's use the minus equation. Substituting the values:
- 0.8 m = xtan15° - (9.81 m/s²)x²/2(4.8 m/s)²(cos15°)²
Solving for x,
x = 2.549 m
However, we only take half of this distance because it was specified that the distance asked before bouncing. Hence, the horizontal distance is equal to 1.27 m.
Answer:
(a). The average daily demand of this subdivision is 2444.44 gallon/min.
(b). The design-demand used to design the distribution system is 2444.44 gallon/min.
Explanation:
Given that,
Area = 1100 acres
Number of house in 1 acres = 4


Per house water demand = 800 g/day/house
(a). We need to calculate the average daily demand of this subdivision
Using formula for average daily demand





The average daily demand of this subdivision is 2444.44 gallon/min.
(b). We need to calculate the design-demand used to design the distribution system
Using formula for the design-demand



Hence, (a). The average daily demand of this subdivision is 2444.44 gallon/min.
(b). The design-demand used to design the distribution system is 2444.44 gallon/min.