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3 years ago

Ls -2 a solution of 4x +3= -5?.

Physics

1 answer:

torisob [31]3 years ago

5 0

Answer:

yes

Explanation:

Let's solve your equation step-by-step.

4x+3=−5

Step 1: Subtract 3 from both sides.

4x+3−3=−5−3

4x=−8

Step 2: Divide both sides by 4.

4x / 4 = −8 / 4

x=−2

Hope it helps,

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2. Describe what would happen to both air temperature and soil temperature if cold weather were to pass through the area.

loris [4]

The air temperature would drop quickly compared to the soil because the difference between solid and gas. But the ground will stay cooler longer than the air because it contains it better than the air.

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4 years ago

. The free throw line in basketball is 4.57 m (15 ft) from the basket, which is 3.05 m (10 ft) above the floor. A player standin

pentagon [3]

Answer:

$\theta = 67.22 degree$

Explanation:

Let say the ball is projected at an angle with horizontal

So here two components of the velocity of the ball is given as

$v_x = 8.15 cos\theta$

$v_y = 8.15 sin\theta$

now the displacement in x direction is given as

$x = v_x t$

$4.57 = (8.15 cos\theta)t$

in y direction it is given as

$y = y_o + v_y t - \frac{1}{2}gt^2$

$3.05 = 2.44 + (8.15 sin\theta) t - 4.9 t^2$

now from above two equations

$0.61 = 4.57 tan\theta - 4.9(\frac{4.57}{8.15 cos\theta})^2$

$0.61 = 4.57 tan\theta - 1.54(1 + tan^2\theta)$

$1.54 tan^2\theta - 4.57 tan\theta + 2.15 = 0$

$\theta = 67.22 degree$

7 0

3 years ago

A 0.413 kg block requires 1.09 N

Virty [35]

Answer:

Explanation:

The equation for this is

f = μ $F_n$ where f is the frictional force the block needs to overcome, μ is the coefficient of static friction, and $F_n = w=mg$ (that means that the normal force is the same as the weight of the block which has an equation of weight = mass times the pull of gravity). Filling in:

1.09 = μ(.413)(9.8) and

μ = $\frac{1.09}{(.413)(9.8)}$ so

μ = .27

5 0

3 years ago

A block of mass m=16.8 kg is sliding on a surface with initial velocity v=23.2 m/s. The block has a coefficient of kinetic frict

Firdavs [7]

Answer:

t = 23.92 s

Explanation:

Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration (m/s²)

We define the x-axis in the direction parallel to the movement of the block and the y-axis in the direction perpendicular to it.

Forces acting on the block

W: Weight of the block : In vertical direction, downward

FN : Normal force : perpendicular to the floor, upward

fk : Kinetic friction force: parallel to the floor and opposite to the movement

F = 86.4 N , in the direction of the motion

Calculated of the W

W= m*g

W= 16.8 kg* 9.8 m/s² = 164.64 N

Calculated of the FN

We apply the formula (1)

∑Fy = m*ay ay = 0

FN - W = 0

FN = W

FN = 164.64 N

Calculated of the fk

fk = μk*FN

fk = 0.426* 164.64 N

fk = 70.13 N

We apply the formula (1) to calculated acceleration of the block:

∑Fx = m*ax , ax= a : acceleration of the block

F - fk = m*a

86.4 -70.13 = (16.8)*(-a)

16.26 = (16.8)*(-a)

a = -(16.26 )/ (16.8)

a = - 0.97 m/s²

Kinematics of the block

Because the block moves with uniformly accelerated movement we apply the following formula :

vf = v₀ + a*t Formula (2)

Where:

t: time interval (m)

v₀: initial speed (m/s)

vf: final speed (m/s)

Data:

v₀ = 23.2 m/s

vf = 0

a = -0.97 m/s²

Time it takes for the block to stop

We replace data in the formula (2) to calculate the time

vf= v₀+a*t

0 = 23.2+( -0.97)*t

(0.97)*t = 23.2

t = 23.2 / (0.97)

t = 23.92 s

7 0

3 years ago

A ball is thrown upward from the top of a building at an angle of 30.0° to the horizontal and with

Ray Of Light [21]

Answer:

See below

Explanation:

Vertical position = 45 + 20 sin (30) t - 4.9 t^2

when it hits ground this = 0

0 = -4.9t^2 + 20 sin (30 ) t + 45

0 = -4.9t^2 + 10 t +45 = 0 solve for t =4.22 sec

max height is at t= - b/2a = 10/9.8 =1.02

use this value of 't' in the equation to calculate max height = 50.1 m

it has 4.22 - 1.02 to free fall = 3.2 seconds free fall

v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL

it will <u>also</u> still have horizontal velocity = 20 cos 30 = 17.32 m/s

total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s

Horizontal range = 20 cos 30 * t = 20 * cos 30 * 4.22 = 73.1 m

8 0

2 years ago

Ls -2 a solution of 4x +3= -5?.​

Ls -2 a solution of 4x +3= -5?.