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ratelena [41]
3 years ago
8

Ls -2 a solution of 4x +3= -5?.​

Physics
1 answer:
torisob [31]3 years ago
5 0

Answer:

yes

Explanation:

Let's solve your equation step-by-step.

4x+3=−5

Step 1: Subtract 3 from both sides.

4x+3−3=−5−3

4x=−8

Step 2: Divide both sides by 4.

4x  / 4  =  −8  / 4

x=−2

Hope it helps,

Please mark me as the brainliest

Thank you

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A woman (mass= 50.5 kg) jumps off of the ground, and comes back down to the ground at a velocity of -8.4 m/s.
Blizzard [7]

Answer:

Approximately 1.6\times 10^{3}\; \rm N.

Explanation:

By the Impulse-Momentum Theorem, the change in this woman's momentum  will be equal to the impulse that is applied to her.

The momentum p of an object is equal to the product of its mass m and velocity v. That is: p = m \cdot v.

Let v(\text{before}) and v(\text{after}) represent the velocity of the woman before and after the landing. Let m represent the woman's mass.

  • The woman's momentum before the landing would be m \cdot v(\text{before}).
  • The woman's momentum after the landing would be m \cdot v(\text{after}).

Therefore, the change in this woman's momentum would be:

\begin{aligned}& \Delta p \\ & = p(\text{after}) - p(\text{before}) \\ &= m \cdot (v(\text{after})- v(\text{before}))\end{aligned}.

On the other hand, impulse is equal to force multiplied by the duration of the force. Let F represent the average force on the woman. The impulse on her during the landing would be F \cdot t.

Apply the Impulse-Momentum Theorem.

  • Impulse: F\cdot t.
  • Change in momentum: m \cdot (v(\text{after})- v(\text{before})).

Impulse is equal to the change in momentum:

F \cdot t = m \cdot (v(\text{after})- v(\text{before})).

After landing, the woman comes to a stop. Her velocity would become zero. Therefore, v(\text{after}) = 0\; \rm m \cdot s^{-1}.

\begin{aligned}F &= \displaystyle \frac{m \cdot (v(\text{after})- v(\text{before}))}{t} \\ &= \frac{50.5\; \text{kg} \times \left(0 \; \mathrm{m \cdot s^{-1}}- 8.4\; \mathrm{m \cdot s^{-1}}\right)}{0.27\; \rm s} \\ &\approx 1.6 \times 10^{3}\; \rm N\end{aligned}.

3 0
4 years ago
A sprinter runs 200m west and 100 m east her displacement is
kykrilka [37]
100m so you will subtract 100m from 200m. and you will get your answer 200m-100m=100m
8 0
4 years ago
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Solve for (b) how many revolutions it takes for the cd to reach its maximum angular velocity in 1.36s?
Digiron [165]

Angular displacement of the cd is 3.25 rev

Explanation:

The question is incomplete. It is not given what is the maximum angular velocity of the cd.

Here we are going to assume that the maximum angular velocity is:

\omega = 30 rad/s

The motion of the cd is an accelerated angular motion, therefore we can use the following suvat equation:

\theta = (\frac{\omega_0 + \omega}{2})t

where:

\theta is the angular displacement of the cd during the time interval t

\omega_0 is the initial angular velocity of the cd

\omega is the final angular velocity

Here we have:

t = 1.36 s

\omega_0 = 0 (assuming the cd starts from rest)

Therefore, the angular displacement of the cd during this time is:

\theta=(\frac{0+30}{2})(1.36)=20.4 rad

And since 1 rev = 2 \pi rad, we can convert into number of revolutions completed:

\theta = 20.4 rad \cdot \frac{1}{2\pi rad/rev}=3.25 rev

Learn more about angular motion:

brainly.com/question/9575487

brainly.com/question/9329700

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8 0
3 years ago
Orchestra instruments are commonly tuned to match an A-note played by the principal oboe. The Baltimore Symphony Orchestra tunes
Nina [5.8K]

Answer:

Δλ = 3*10⁻³ m.

Explanation:

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       v = \lambda* f  (1)

       where v is the speed, λ is the wavelength and f is the frequency.

  • Rearranging terms, we can get λ from the other two parameters, as follows:

       \lambda = \frac{v}{f}  (2)

  • Since v is constant for sound at 343 m/s, we can find the different wavelengths at different frequencies, as follows:

        \lambda_{1} =\frac{v}{f_{1}} = \frac{343m/s}{440(1/s)} = 0.779 m  (3)

        \lambda_{2} =\frac{v}{f_{2}} = \frac{343m/s}{442(1/s)} = 0.776 m  (4)

  • The difference between both wavelengths, is just the difference between (3) and (4):

       \Delta \lambda = \lambda_{1} - \lambda_{2} = 0.779 m - 0.776m = 3e-3 m (5)

       ⇒ Δλ = 3*10⁻³ m.

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1. A change in which one or more substances are converted into new substances is a
Ratling [72]

Answer:

<u>CHEMICAL CHANGE</u>:

A change in which one or more substances are converted into new substances is a  <em>chemical change</em>.

<u>EXPLANATION:</u>

Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.

<u>EXAMPLE:</u>

<em>Examples of Chemical Change in Everyday Life </em>

Burning of paper and log of wood.

Digestion of food.

Boiling an egg.

Chemical battery usage.

Electroplating a metal.

Baking a cake.

Milk going sour.

Various metabolic reactions that take place in the cells.

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