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2 years ago

A hydraulic system is used to lift a 20,000 N vehicle in an auto garage. If the vehicle sits on

Physics

1 answer:

ollegr [7]2 years ago

7 0

Answer:

Explanation:

Area covered by the vehicle on the piston A1 = 0.5 m2 Weight of the vehicle, F1 = 2000 kg × 9.8 m s-2 Area on which force F2 is applied, A = 0.03 m2 P1 = P2 ; F 1 A 1 F1A1 = F 2 A 2 F2A2 and F2 = F 1 A 1 F1A1 A2 ; F2 = (2000 × 9.8) 0.03 0.5 0.030.5 = 1176 NRead more on Sarthaks.com - https://www.sarthaks.com/957542/hydraulic-system-used-lift-2000-vehicle-in-an-auto-garage-if-the-vehicle-sits-on-piston-area

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Answers are - A 235 N B 376 N C 271 N D 188 N E 470 N

amm1812

Answer:

Explanation:

8 0

2 years ago

A student drops a ball off the top of building and records that the ball takes 3.32s to reach the ground (g = 9.8 m/s^2). What i

slega [8]

Answer:

Explanation:

Here's what we know because it was given to us:

a = -9.8 m/s/s and

time = 3.32 seconds

Here's what we know because we rock physics:

v₀ = 0 (because the object was held still before it was dropped).

Here's the equation that ties all that info together in a single one-dimensional equation:

v = v₀ + at

Filling in and solving for v:

v = 0 + (-9.8)(3.32) and

v = -33m/s

The velocity is negative because the object is moving downwards and up is positive (but you knew that already too!)

7 0

2 years ago

How do flower petals help a flowering plant reproduce?

Verdich [7]

the flower of a plant will attract an animal such as a bee that will take the pollen from the plant and transmit it to another plant. this shows that flowers help plant reproduce as they will attract an animal that will carry reproductive material to another plant

6 0

2 years ago

Read 2 more answers

Suppose I have a spherical insulating shell with inner radius r and outer radius R. The shell has a uniformly distributed charge

a_sh-v [17]

Answer:

3Q / 4 pi (R^3 - r^3)

Explanation:

Charge density = charge / volume

volume of a spherical shell = $\frac{4}{3} \pi(R^{3} - r^{3})$

4 0

3 years ago

A block of aluminum with a volume of 10 cm3 is placed in a beaker of water filled to the brim. Water overflows. The same is done

mihalych1998 [28]

Answer:

a) Both blocks displace the same amount of water.

Explanation:

Specific gravity (S.G.) is a quantity that tells how much and object is submerged on water and is given by:

$S.G=\frac{\rho_{block}}{\rho_{fluid}}$

with ρ the densities

Density of water is $997 \frac{kg}{m^{3}}$ and density of aluminum is $2712 \frac{kg}{m^{3}}$

So:

$S.G=\frac{2712}{997}=2.72$

A S.G. value bigger than one means the object is totally submerged so the water displaced is equal to the volume of the cube.

For the lead (density = $11340\frac{kg}{m^{3}}$ ) block we're going to calculate specific gravity in this case:

$S.G=\frac{11340}{997}=11.37$

Again S.G gravity is bigger than 1, so the lead block is totally submerged too, that implies the volume of water displaced is the volume of the block, that is the same volume as the aluminum block, so a is the correct one.

7 0

3 years ago