The amplitude of the wave on the given sinusoidal wave graph is 10 cm.
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What is amplitude of wave?</h3>
The amplitude of a wave is the maximum displacement of a wave. This is the highest vertical position of the wave from the origin.
Amplitude of the wave is calculated as follows;
From the graph, the amplitude of the wave or maximum displacement of the wave is 10 cm.
Thus, the amplitude of the wave on the given sinusoidal wave graph is 10 cm.
Learn more about wave amplitude here: brainly.com/question/25699025
V₀ = V₁ + 2ax
V₀ = final velocity which is 0 m/s
V₁ = initial velocity which is 20 m/s
x = distance which is 60-(0.5 x 20) =50m
this is because his reaction time is 0.5 sec so he traveled 10m before stepping on the break paddle.
a= (V₀-V₁) / 2x
= (0-20) / 2*50
= -0.2m/s
the negative is because it is a deceleration speed hence it is 0.2m/s
Answer:
1. Nismo: 
2. Ferdinand:
, Shelby: 
3. Enzo: 
4. Lotus: 
Explanation:
The luminosity of a star is the amount of light it emits from its surface. The luminosity is an intrinsic property of the star. Apparent brightness is how bright the star appears to a detector on Earth. Apparent brightness is not an intrinsic property of the star; it depends on the location of the observer.
As light travels towards an observer, it spreads out and covers a larger area, reducing the intensity. Thus the apparent brightness is inversely proportionate to the square of the distance between the star and observer.
Apparent brightness can be calculated by the formula below:

Where,
is apparent brightness,
is luminosity,
is the distance between the star and observer
Enzo: 200 LSun , 20 ly



Ferdinand: 400 LSun , 20 ly



Nismo: 100 LSun , 8 ly



Lotus: 400 LSun , 40 ly



Shelby: 100 LSun , 10 ly



Apparent brightness of stars is summarized as below. Absolute values are considered as units are unspecified
Enzo: 
Ferdinand: 
Nismo: 
Lotus: 
Shelby: 
Organized in order of apparent brightness
1. Nismo: 
2. Ferdinand:
, Shelby: 
3. Enzo: 
4. Lotus: 
Answer:
Option B. 2.8 s
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 27 m/s
Angle of projection (θ) = 30
Acceleration due to gravity (g) = 9.8 m/s²
Time of flight (T) =?
The time of flight of the ball can be obtained as follow:
T = 2uSineθ / g
T = 2 × 27 × Sine 30 / 9.8
T = 2 × 27 × 0.5 / 9.8
T = 27 / 9.8
T = 2.8 s
Therefore, time of flight of the ball is 2.8 s