- Displacement = 10 m
- Time = 5 s
- We know,

- Therefore, the car's velocity

<h3>Answer:</h3>
The car's velocity is 2 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
The air fraction to be removed is 0.11
Given:
Initial temperature, T =
= 283 K
Pressure, P = 250 kPa
Finally its temperature increases, T' =
= 318 K
Solution:
Using the ideal gas equation:
PV = mRT
where
P = Pressure
V = Volume
m = no. of moles of gas
R = Rydberg's Constant
T = Temperature
Now,
Considering the eqn at constant volume and pressure, we get:
mT = m'T'
Thus
(1)
Now, the fraction of the air to be removed for the maintenance of pressure at 250 kPa:

From eqn (1):


False ...................