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lukranit [14]
4 years ago
6

Which elements are included in Group 5A?

Chemistry
2 answers:
Molodets [167]4 years ago
7 0

Answer : The elements include in group 5A are, Nitrogen, phosphorous, arsenic, antimony and bismuth.

Explanation :

According to the modern periodic table, the group 5A is known as group 15. And it is also known as nitrogen family.

The elements present in group 5A are, nitrogen (N), phosphorous (P), arsenic(As), antimony(Sb) and bismuth (Bi).

The general electronic configuration of group 5A elements is, ns^2np^3

The number of valance electrons present in group 5A elements are, 5

Hence, the elements include in group 5A are, Nitrogen, phosphorous, arsenic, antimony and bismuth.

nydimaria [60]4 years ago
6 0
Nitrogen, Phosphorous, arsenic, antimony, bismuth
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dezoksy [38]

Answer:

that results in an alcohol and a carboxylic acid.

Explanation:

Saponification is a chemical reaction process of alkaline hydrolysis of esters(R'COOR group) by which soap is obtained.

For Example, when a base such as sodium hydroxide [NaOH]  is used to hydrolyze an ester, the products are a carboxylate salt and an alcohol. Because soaps are prepared by the alkaline hydrolysis of fats and oils.

In a saponification reaction, alkaline hydrolysis of fats and oils with sodium hydroxide  yields propane-1,2,3-triol and the corresponding sodium salts of the component fatty acids.

i.e  Fat or oil + caustic alkali ⇒ Soap + propane-1,2,3-triol

As a specific example, ethyl acetate and NaOH react to form sodium acetate and ethanol:

The reaction goes to completion in the image below:

8 0
3 years ago
Balance the following equation. Choose "blank" if no coefficient other than 1 is needed.
Ann [662]

Explanation:

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8 0
3 years ago
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Which set of coefficients will balance this chemical equation?
Montano1993 [528]

Answer:

Option B is correct = 1,3

Explanation:

Chemical equation:

C₂H₄ + O₂     →    CO₂ + H₂O

Balanced chemical equation:

C₂H₄ + 3O₂     →    2CO₂ + 2H₂O

Step 1:

Left side                      Right side

C = 2                           C = 1

H = 4                           O = 3

O = 2                           H = 2

Step 2:

C₂H₄ + O₂     →    2CO₂ + H₂O

Left side                      Right side

C = 2                           C = 2

H = 4                           O = 5

O = 2                           H = 2

Step 3:

C₂H₄ + O₂     →    2CO₂ + 2H₂O

Left side                      Right side

C = 2                           C = 2

H = 4                           O = 6

O = 2                           H = 4

Step 4:

C₂H₄ + 3O₂     →    2CO₂ + 2H₂O

Left side                      Right side

C = 2                           C = 2

H = 4                           O = 6

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5 0
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Answer:

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4. You have to decide for yourself if you’d like it better or worse

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kodGreya [7K]

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The conclusion of the experiment was that the atom contained a small dense positively charged nucleous and negative particles (electrons) surroundiing the nucleous. Being the space in between the nucleous and the electrons empty.


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