Answer:
592000 J
Explanation:
We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:
1 Pa = 1 Kg/ms²
Therefore,
3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²
Next, we shall determine the workdone.
Workdone is given by the following equation:
Workdone (Wd) = pressure (P) × change in volume (ΔV)
Wd = PΔV
With the above formula, the work done can be obtained as follow:
Pressure (P) = 3.7×10⁵ Kg/ms²
Change in volume (ΔV) = 1.6 m³
Workdone (Wd) =?
Wd = PΔV
Wd = 3.7×10⁵ × 1.6
Wd = 592000 Kgm²/s²
Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:
1 Kgm²/s² = 1 J
Therefore,
592000 Kgm²/s² = 592000 J
Therefore, the Workdone is 592000 J.
You’re correct hope this helps :)
Answer:
8.6*10^5N
Explanation:
Pressure of the water = density of water * height of the water * acceleration due to gravity
Pressure of water = 1000*9.81*(2.5 + 8.50)
Pressure of the water = 107910 = 1.08*10^5
And Pressure = force / A
Force = Pressure * A(surface area of the container)
Force = 1.08*10^5 * 8 = 863280 = 8.6*10^5N
Answer: box one is chemical energy and box 2 is absorbed energy
Explanation:
charge stored in the capacitor=3.29 x 10⁻⁴ C
Explanation:
we use the formula
Q= C V
Q= charge
C= capacitor=25.3 μF= 25.3 x 10⁻⁶ F
V= voltage= 13 V
Q=(25.3 x 10⁻⁶ ) (13)
Q= 3.29 x 10⁻⁴ C