Answer:A) 19.8 seconds
B) 467.5 metres
Explanation: 100km/hr = 27.78m/s
So, it covers 27.78 metres in one second
Take the time it would cover 550m as x
Therefore 27.78m = 1second
550m = x
Cross multiplying
27.78x = 550m
Divide both sides by the coefficient of x
x = 550÷27.78
x = 19.8seconds
B) distance = speed × time
Speed = 85km/hr = 23.61m/s
Time = 19.8seconds
Therefore,
Distance = 23.61 × 19.8
Distance = 467.5m
The answer is 167 pounds.
At 100 km/hr, the car's kinetic energy is
KE = (1/2) (mass) (speed)²
KE = (1/2) (1575 kg) ( [100 km/hr] x [1000 m/km] x [1 hr/3600 sec] )²
KE = (787.5 kg) (27.78 m/s)²
KE = 607,639 Joules
In order to deliver this energy in 2.9 seconds, the engine must supply
(607,639 J / 2.9 sec) = 209,531 watts
<em>Power = 281 HP</em>
Answer:
350 ft/s²
Explanation:
First, convert mph to ft/s.
58 mi/hr × (5280 ft/mi) × (1 hr / 3600 s) = 85.1 ft/s
Given:
v₀ = 85.1 ft/s
v = 0 ft/s
t = 0.24 s
Find: a
v = at + v₀
a = (v − v₀) / t
a = (0 ft/s − 85.1 ft/s) / 0.24 s
a = -354 ft/s²
Rounded to two significant figures, the magnitude of the acceleration is 350 ft/s².