The distance from the Earth to the Sun is 92.96 million mi.
Answer:
The ball would hit the floor approximately
after leaving the table.
The ball would travel approximately
horizontally after leaving the table.
(Assumption:
.)
Explanation:
Let
denote the change to the height of the ball. Let
denote the time (in seconds) it took for the ball to hit the floor after leaving the table. Let
denote the initial vertical velocity of this ball.
If the air resistance on this ball is indeed negligible:
.
The ball was initially travelling horizontally. In other words, before leaving the table, the vertical velocity of the ball was
.
The height of the table was
. Therefore, after hitting the floor, the ball would be
below where it was before leaving the table. Hence,
.
The equation becomes:
.
Solve for
:
.
In other words, it would take approximately
for the ball to hit the floor after leaving the table.
Since the air resistance on the ball is negligible, the horizontal velocity of this ball would be constant (at
) until the ball hits the floor.
The ball was in the air for approximately
and would have travelled approximately
horizontally during the flight.
To solve this problem we will apply the concepts related to the balance of Forces, the centripetal Force and Newton's second law.
I will also attach a free body diagram that allows a better understanding of the problem.
For there to be a balance between weight and normal strength, these two must be equivalent to the centripetal Force, therefore


Here,
m = Net mass
= Angular velocity
r = Radius
W = Weight
N = Normal Force

The net mass is equivalent to

Then,

Replacing we have then,

Solving to find the angular velocity we have,

Therefore the angular velocity is 0.309rad/s
Answer:
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We live on the troposphere