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just olya [345]
3 years ago
15

Quantity A of an ideal gas is at absolute temperature T, and a second quantity B of the same gas is at absolute temperature 2T.

Heat is added to each gas, and both gases are allowed to expand isothermally.If both gases were initially at the same absolute temperature, would they still undergo the same entropy change?No, gas A would undergo the greater entropy change.No, gas B would undergo the greater entropy change.Yes, both gases would have the same entropy.
Physics
1 answer:
Ira Lisetskai [31]3 years ago
5 0

Answer: Yes both gases would have the same entropy.

Explanation:

The formula for the change in the entropy is as follows,

\Delta S = \frac{Q}{T}

Here, \Delta S is the change in the entropy, Q is the heat transfer and T is the temperature.

If the temperature of the system increases then there will be increase in the entropy as the randomness of the system increases.

In the given problem, if the both gases were initially at the same absolute temperature. Then there will be same entropy change in both gases.

Therefore, yes both gases would have the same entropy.

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The weight of an object is measured in air to be 7.0 N. The
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Answer:

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Explanation:

Apparent weight of a body immersed in water is the actual weight of object minus buoyant force

Given in the question that;

Weight of object in air = 7.0 N

Apparent weight of object = 4.0 N

4.0 N = 7.0 N - Buoyant force

Buoyant force = 7.0 - 4.0 = 3.0 N

In this case, the buoyant force is less than weight of the object thus the object will sink.

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3 years ago
Which statement describes how the photoelectric effect causes an electric
alina1380 [7]

Answer:

A. Light acts as particles, causing electrons on the surface it strikes to be destroyed.

Explanation:

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8 0
3 years ago
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If the kinetic and potential energy in a system are equal, then the potential energy increases. What happens as a result?
Fittoniya [83]

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The Kinetic Energy decreases. The Total Energy stays the same

Explanation:

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7 0
3 years ago
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Answer = 2700km
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Hope that helped =)
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