The range of force exerted at the end of the rope is 285.7 N to 1,000 N.
<h3>Net horizontal force of the cylinder</h3>
The net horizontal force of the cylinder when it is at equilibrium position is determined by applying Newton's second law of motion.
∑F = 0
F - μFn = 0
F - 0.2(5,000) = 0
F - 1,000 = 0
F = 1,000 N
The strength of the applied force increases as the number of turns of the rope increases.
minimum force = total force/number of turns of rope
minimum force = 1,000/3.5
minimum force = 285.7 N
Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.
Learn more about Newton's second law of motion here: brainly.com/question/3999427
Answer:
Mass of object (m) = 5.102 kg
Explanation:
Given:
Horizontal Force (F) = 50 N
Find:
Mass of object (m) = ?
Computation:
We know that, acceleration due to gravity (g) = 9.8 m/s²
⇒ Horizontal Force (F) = mg
⇒ 50 N = m (9.8 m/s²)
⇒ Mass of object (m) = 50 / 9.8
⇒ Mass of object (m) = 5.102 kg
Mass of object (m) is 5.1 kg (Approx)
That statement is wrong.
Domestic violence could happen to anyone.
There are a lot of cases in which the domestic violence's victims are men or elderly people.
Answer:
D) 25 m/s
Explanation:
In order to solve this problem we must use the following kinematics equation.

where:
Vf = final speed [m/s]
Vi = initial speed = 0
a = acceleration = 5[m/s^2]
t = time = 5[s]
After 5 seconds the acceleration is equal to 5 [m/s^2]
Now replacing the values in the equation:
Vf = 0 + (5*5)
Vf = 25[m/s]
A large body of matter with no definite shape.
The SI unit is-kilogram(kg).