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Brilliant_brown [7]
3 years ago
12

2. A _______ is a device used to measure the intensity of electromagnetic waves, such as light waves and radio waves. A. baromet

er B. strain gauge C. thermistor D. thermocouple
Physics
1 answer:
kramer3 years ago
8 0

Answer: it is C

The thermistor

Explanation:

 Thermistors (temperature-sensitive, or thermal, resistors) are used as temperature-measuring devices and in electrical circuits to compensate for temperature variations of other components. They are also used to measure radio-frequency power and radiant power, such as infrared and visible light.

To measure the intensity of the electromagnetic wave after knowing the frequency, we can calculate it by using fast fourier transformations (FFT).

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How does the observed pitch of the buzzer change as it moves
andriy [413]

The answer is

Pitch of the buzzer increased (higher tone) as it moves towards the observer

5 0
2 years ago
A 12.0 cm object is 9.0 cm from a convex mirror that has a focal length of -4.5 cm. What is the distance of the image from the m
Rasek [7]

Answer:

- 3 cm

Explanation:

From the mirror formula;

1/f = 1/v + 1/u ; where f is the focal length, v is the image distance, and u is the object distance.

1/-4.5 = 1/9 + 1/v

1/v = -1/4.5 - 1/9

    = -1/3

Therefore;

v = -3 cm

Hence;

Image distance is - 3cm

5 0
3 years ago
what type of energy appears when a gymnast jumps on to a spring board? Question is on energy stores!Thanks
Brrunno [24]
Hello There!

It is Spring potential energy. Also called Elastic potential energy.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
5 0
3 years ago
HELP ASAP!! i’ll mark you the brainliest!!
Triss [41]

Answer:

yes

Explanation:

6 0
2 years ago
A 800-gram grinding wheel 27.0 cm in diameter is in the shape of a uniform solid disk. (We can ignore the small hole at the cent
SSSSS [86.1K]

Explanation:

d = Diameter of wheel = 27 cm

r = Radius = \frac{d}{2}=\frac{27}{2}=13.5\ cm

m = Mass of wheel = 800 g

\omega_i = Initial angular velocity = 245\times \frac{2\pi}{60}\ rad/s

Equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-245\times \frac{2\pi}{60}}{50}\\\Rightarrow \alpha=-0.51312\ rad/s^2

Moment of inertia is given by

M=\frac{1}{2}mr^2\\\Rightarrow M=\frac{1}{2}\times 0.8\times 0.135^2\\\Rightarrow M=0.00729\ kgm^2

Torque is given by

\tau=I\alpha\\\Rightarrow \tau=0.00729\times -0.51312\\\Rightarrow \tau=-0.0037406448\ Nm

The torque the friction exerts is -0.0037406448 Nm

For more information on torque and moment of inertia refer

brainly.com/question/13936874

brainly.com/question/3406242

7 0
3 years ago
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