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Brilliant_brown [7]
4 years ago
12

2. A _______ is a device used to measure the intensity of electromagnetic waves, such as light waves and radio waves. A. baromet

er B. strain gauge C. thermistor D. thermocouple
Physics
1 answer:
kramer4 years ago
8 0

Answer: it is C

The thermistor

Explanation:

 Thermistors (temperature-sensitive, or thermal, resistors) are used as temperature-measuring devices and in electrical circuits to compensate for temperature variations of other components. They are also used to measure radio-frequency power and radiant power, such as infrared and visible light.

To measure the intensity of the electromagnetic wave after knowing the frequency, we can calculate it by using fast fourier transformations (FFT).

You might be interested in
Connelly cuts a solid object in half. What happens to the mass, volume, and density of the object that Connelly cuts? A)The mass
amm1812
I think the correct answer would be D. After cutting the solid object in half, the mass and volume are both divided by two, but the density remains the same. The mass and volume would change accordingly to satisfy the law of conservation of mass which states that mass cannot be created or destroyed. So, after dividing the object the sum of the mass of the two parts should be equal to the original mass of the object. This would also be the same for the volume of the objects. Density is the ratio of mass and volume and, since the mass and volume change accordingly, the value of the density would still be the same regardless of the object being divided.
3 0
4 years ago
An uncharged capacitor is connected to the terminals of a 4.0 V battery, and 6.0 μC flows to the positive plate. The 4.0 V batte
Ugo [173]

Answer:

1 μC extra charge will be flow here

Explanation:

Given data

battery V1 = 4.0 V

flows Q1 =  6.0 μC

replace battery V2 = 7.0 V

to find out

what happen if we replace battery

solution

we apply here principal of capacitor

that is Q directly proportional voltage

so we say Q2/Q1 = V2/ V1

put all value here

Q2/Q1 = V2/ V1

Q2/6 = 7/ 6

Q2 = 7

so we see here 7 μC will be flow

and Q = Q2 - Q1 = 7 - 6 = 1 μC

so we also say that 1 μC extra charge will be flow here

5 0
4 years ago
An object is placed 100 cm in front of a diverging lens of focal length -25cm. A converging lens of focal length 33 1/3 cm is pl
bagirrra123 [75]
We use 1/o + 1/i = 1/f  where o is the distance of the object, i as distance of the image and f is the focal length.
Substituting, <span>1/ 100 + 1 / i = - 1 /25 </span>
<span>i = - 20 cm </span>

<span>For the case of the problem,</span>

<span>o = (20 + 30)  = 50 cm </span>

<span>f = 33.33. </span>Using 1<span> / i + 1 / o = 1/f , </span><span> </span><span>i = 100 cm </span>

<span>M = magnification = - i / o </span>

<span>m1 = -(-20)/100 = 20/100 = 0.2 </span>

<span>m2 = -100/50 = -2 </span>

<span>M = m1*m2 = -2 x 0.2 = -0.4.</span>
8 0
4 years ago
Coulomb's law is similar to newton's law of gravitation in several ways. which one of the statements is not a similarity between
PIT_PIT [208]

The only dissimilarity between Coulomb's law and Newton's law of gravitation other than the type of force considered is Newton's law only considers negative force while Coulomb's law considers both forces.

In these contexts, it is considered that repulsive forces are positive and attractive forces are negative. So, Newton's law of gravitation considers gravitational force which only attracts. So, Newton's law of gravitation takes only negative force into account while Coulomb's law considers both electric charges.

According to Newton's law of gravitation,

F = G m_{1} m_{2} / r^{2}

According to Coulomb's law

F = k q_{1} q_{2} / r^{2}

Therefore, the only dissimilarity between Coulomb's law and Newton's law of gravitation other than the type of force considered is Newton's law only considers negative force while Coulomb's law considers both positive and negative forces.

To learn more about Coulomb's law

brainly.com/question/506926

#SPJ4

4 0
2 years ago
An elastic circular bar is fixed at one end and attached to a rubber grommet at the other end. The grommet functions as a torsio
Artist 52 [7]

Answer:

2.1 rad(anticlockwise).

Explanation:

So, we are given the following data or parameters or information in the question above:

=> "The torsional stiffness of the spring support is k = 50 N m/rad. "

=> "If a concentrated torque of mag- nitude Ta = 500 Nm is applied in the center of the bar"

=> "L = 300 mm Assume a shear modu- lus G = 10 kN/mm2 and polar monnent of inertia J = 2000 mln"

Hence;

G × J = 10 kN/mm2 × 2000 mln = 20 Nm^2.

Also, L/2 = 300 mm /2 = 0.15 m (converted to metre).

==> 0.15/20 (V - w) + θ = 0.

==> 0.15/20 (V - w ) = -θ.

Where V = k = 50 N m/rad

w = 183.3 θ.

Therefore, w + Vθ = 500 Nm.

==> 183.3 + 50 θ = 500 Nm.

= 6.3

Anticlockwise,

θ = 2.1 rad.

4 0
3 years ago
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