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3 years ago

The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is_____

1 answer:

3 0

When you are talking about calculating the kinetic energy of an object, the formula is as stated:

Ek =1/2mv²

Where m is mass and v is velocity. Sub all those numbers in and you'll get 25J of kinetic energy.

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An open pipe is 1.42 m long

lora16 [44]

Answer:

the fundamental frequency produced by the open pipe is 120.78 Hz

Explanation:

Given;

length of the open pipe, L = 1.42 m

speed of sound in air, v = 343 m/s

The length of the open pipe for the fundamental frequency is equivalent to half of wavelength;

$L = \frac{\lambda}{2} \\\\\lambda = 2L$

The fundamental frequency produced by the open pipe is calculated as;

$f_o = \frac{v}{\lambda} \\\\f_o = \frac{v}{2L} \\\\f_o = \frac{343}{2 \times 1.42} \\\\f_o = 120.78 \ Hz$

Therefore, the fundamental frequency produced by the open pipe is 120.78 Hz

6 0

3 years ago

a waterwheel built in Hamah, Syria, has a radius of 20 m . If the tangential velocity at the wheels edge is 7.85 m/s , what is t

gtnhenbr [62]

Answer:

3.08m/s²

Explanation:

Given parameters:

Radius = 20m

Tangential velocity = 7.85m/s

Unknown:

Centripetal acceleration = ?

Solution:

Centripetal acceleration is the acceleration of a body along a circular path.

it is mathematically given as;

a = $\frac{v^{2} }{r}$

v is the tangential velocity

r is the radius

a = $\frac{7.85^{2} }{20}$ = 3.08m/s²

4 0

3 years ago

A 0.5 kg ball is tied to a swung in a circle with a radius of 0.400m.If the ball is accelerating at 58.8 m/s^2,what is the tange

jeka57 [31]

If the acceleration is centripetal then the formula is a=v^2/r
Plug in 58.8=v^2/.400 solve for v
V=12.12 m/s

5 0

3 years ago

The sun is more massive than the moon, but the sun is farther from the earth. Which one exerts a greater gravitational force on

love history [14]

Answer:

178.4 times

Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

$F_G = G\frac{M_1M_2}{R^2}$

where $G =6.67408 × 10^{-11} m^3/kgs^2$ is the gravitational constant on Earth. $M_1, M_2$ is the masses of the 2 objects. and R is the distance between them.