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jolli1 [7]
3 years ago
13

How can the rate of evaporation of a liquid be increased?​

Physics
2 answers:
Nadusha1986 [10]3 years ago
5 0

When air is blown above the surface of liquid, it will take away the liquid carrying air particles from the air above the liquid, resulting in decrease in humidity and increase in rate of evaporation.

Hope that this was helpful :)

lapo4ka [179]3 years ago
5 0

Answer:

Temperature: The greater the temperature of the liquid and its surroundings, the faster the rate of evaporation.The Surface area occupied by the liquid: Since evaporation is a surface phenomenon, the greater the surface area occupied by the liquid, the quicker it undergoes evaporation.

Explanation:

Hope this helps!

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The answer is C

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Explanation:

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The answer that you are looking for is D.

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A long solenoid that has 1 200 turns uniformly distributed over a length of 0.420 m produces a magnetic field of magnitude 1.00
Fantom [35]

Answer:

<h2>The current required  winding is  2.65*10^-^2 mA</h2>

Explanation:

We can use the expression B=μ₀*n*I-------1 for the magnetic field that enters a coil  and

n= N/L (number of turns per unit length)

Given data

The number of turns n= 1200 turns

length L= 0.42 m

magnetic field B= 1*10^-4 T

μ₀= 4\pi*10^-^7 T.m/A

Applying the equation  B=μ₀*n*I

I= B/μ₀*n

I= B*L/μ₀*n

I= \frac{1*10^-^4*0.42}{4\pi*10^-^7*1.2*10^3 }

I= 2.65*10^-^2 mA

8 0
3 years ago
A 62.0 kg water skier at rest jumps from the dock into a 775 kg boat at rest on the east side of the dock. If the velocity of th
Dominik [7]

Answer:

v = 0.33 m/s

Explanation:

The final velocity of the skier and boat can be calculated by conservation of the lineal momentum:

m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{1f} + m_{2}v_{2f}

<u>Where:</u>

m1: is the mass of the water skier = 62.0 kg

m2: is the mass of the boat = 775 kg

v1i: is the initial velocity of the water skier = 4.50 m/s    

v1f: is the final velocity of the water skier = ?

v2i: is the initial velocity of the boat = 0

v2f: is the final velocity of the boat = ?

Since the final velocity of the skier is the same that the final velocity of the boat, we have:      

m_{1}v_{1i} + m_{2}v_{2i} = m_{1}v_{f} + m_{2}v_{f}  

m_{1}v_{1i} + 0 = v_{f}(m_{1} + m_{2})  

v_{f} = \frac{62.0 kg*4.50 m/s}{(62.0 kg + 775 kg)}  

v_{f} = 0.33 m/s  

Therefore, the final velocity of the skier and boat is 0.33 m/s.

I hope it helps you!

5 0
3 years ago
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