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3 years ago

How can the rate of evaporation of a liquid be increased?

2 answers:

Nadusha1986 [10]3 years ago

5 0

When air is blown above the surface of liquid, it will take away the liquid carrying air particles from the air above the liquid, resulting in decrease in humidity and increase in rate of evaporation.

Hope that this was helpful :)

lapo4ka [179]3 years ago

5 0

Answer:

Temperature: The greater the temperature of the liquid and its surroundings, the faster the rate of evaporation.The Surface area occupied by the liquid: Since evaporation is a surface phenomenon, the greater the surface area occupied by the liquid, the quicker it undergoes evaporation.

Explanation:

Hope this helps!

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It could rotate while not advancing distance

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3 years ago

A 1.5 wire carries a 2 a current when a potential difference of 87 v is applied. What is the resistance of the wire

Dmitry_Shevchenko [17]

Ohm's law states that V = IR

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3 years ago

The earth and the moon are attracted to each other by gravitational force. Does the earth attract the moon with a force that is

KengaRu [80]

Answer:

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2 years ago

Help me please my teacher requires work!!

emmainna [20.7K]

The change needed is from 8 to 28, a change of 20 m/s. At a rate of 2m/s/s it will take 10 seconds for it to happen (2x10=20). I hope this helps.

8 0

3 years ago

Please help 2.

Mariulka [41]

Answer:

The new volume of the balloon is 8.8 L

Explanation:

Charles's Law consists of the relationship between the volume and the temperature of a certain amount of ideal gas, which is kept at a constant pressure. This law establishes that the volume is directly proportional to the temperature of the gas, that is to say that if the temperature increases, the volume of the gas increases and that on the contrary if the temperature of the gas decreases, the volume decreases.

In other words, Charles's law states that when the amount of gas and pressure are kept constant, the ratio between the volume and the temperature will always have the same value:

$\frac{V}{T}=k$

Having a certain volume of gas V1 that is at a temperature T1, by varying the volume of gas to a new value V2, then the temperature will change to T2, and it will be fulfilled:

$\frac{V1}{T1}=\frac{V2}{T2}$

In this case:

V1= 8.5 L
T1= 294 K
V2= ?
T2= 305 K

Replacing:

$\frac{8.5 L}{294 K}=\frac{V2}{305 K}$

Solving:

$V2=305 K*\frac{8.5 L}{294 K}$

V2=8.8 L

<u><em>The new volume of the balloon is 8.8 L</em></u>

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3 years ago

How can the rate of evaporation of a liquid be increased?​

How can the rate of evaporation of a liquid be increased?