All categories

3 years ago

Why is u-235 a good isotope of uranium for creating chain reactions?

1 answer:

5 0

<span>under specific conditions it can promptly be taken apart easily, yielding a great deal of energy . It is subsequently said to be 'fissile' and we utilize the articulation 'atomic splitting'. In the interim, similar to every single radioactive isotope, they rot.</span>

You might be interested in

The atoms of gold would be the same as the atoms of iron and have the same properties. True or false?

Nina [5.8K]

Answer:

false

Explanation:

not too sure sorry if im wrong

7 0

3 years ago

For an ideal gas, classify the pairs of properties as directly or inversely proportional. You are currently in a sorting module.

vredina [299]

Answer:

the result for the following are (a) P is directly proportional to n

(b) V is directly proportional to T (c) P is directly proportional to T (d) T is inversly proportional to V (e) P is inversely proportional to V

6 0

2 years ago

Why is the Atlantic Ocean growing larger, but the Pacific Ocean is growing smaller?

Anastasy [175]

Answer:

A.The Atlantic Ocean has more mid-ocean ridges than the Pacific Ocean so that keeps it growing larger.

Explanation:

Atlantic ocean is getting bigger because of the presence of spreading centers (divergent plate boundary). ... Pacific Ocean is getting smaller because the pacific plate is subducting along the subduction zones. Subduction zones are areas where old, dense plate subducts beneath a less dense plate.

7 0

3 years ago

Is always

Studentka2010 [4]

Answer:

o atom, smaller, anion is the right answer of the following

7 0

3 years ago

You are given a solid that is a mixture of na2so4 and k2so4.

Murljashka [212]

Here we have to calculate the amount of $SO_{4}^{2-}$ ion present in the sample.

In the sample solution 0.122g of $SO_{4}^{2-}$ ion is present.

The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-

K₂SO₄ = 2K⁺ + $SO_{4}^{2-}$

(Na)₂SO₄=2Na⁺ + $SO_{4}^{2-}$

Thus, BaCl₂+ $SO_{4}^{2-}$ = BaSO₄↓ + 2Cl⁻ .

(Na)₂SO₄ and K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of $SO_{4}^{2-}$ ion is precipitated in this reaction.

The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.

Now the molecular weight of BaSO₄ is 233.3 g/mol.

We know the molecular weight of sulfate ion ( $SO_{4}^{2-}$ ) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of $SO_{4}^{2-}$ ion is present.

Or. we may write in 233.3 g of BaSO₄ 96.06 g of $SO_{4}^{2-}$ ion is present. So in 1 g of BaSO₄ $\frac{96.06}{233.3}=0.411$ g of $SO_{4}^{2-}$ ion is present.

Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of $SO_{4}^{2-}$ ion is present.

5 0

3 years ago