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arlik [135]
3 years ago
10

Help asap

Physics
1 answer:
Alecsey [184]3 years ago
4 0

q1 ... No diagram.

q2 ... c

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How much total work is done by the force in lifting the elevator from 0.0 m to 9.0 m?
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The total work is

         (mass of the elevator, kg) x (9.8 m/s²) x (9.0 m)           Joules .
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How much heat is needed to change the temperature of 3 grams of gold (c = 0.129 ) from 21°C to 363°C? The answer is expressed to
Temka [501]

Q= mcΔT

Where Q is heat or energy

M is mass, c is heat capacitance and t is temperature

You have to convert Celsius into kelvin in order to use this formula I believe

Celsius + 273 = Kelvin

21 + 273 = 294K

363 + 273 = 636K

Now...

Q= (0.003)(0.129)(636-294)

Q= 0.132 J if you are using kilograms, in terms of grams which seems more appropriate the answer would be 132J of energy.  

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3 years ago
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Rafe is placing his car on a lift to change the oil and oil filter. He needs to drive up the lift 1.5 meters and the lift raises
jeyben [28]

Answer:

104 IMA

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7 0
3 years ago
In a paragraph, contrast the characteristics between anorexia and bulimia
FinnZ [79.3K]
Bulimia nervosa is similar in many ways because the individual is obsessed with their weight and wants to continuously lose weight to achieve their idea of a 'perfect' body shape. But with bulimia, there are periods of binging and purging. This means that the individual with bulimia may go through a period where they eat an excessive amount of food and then purge by using exercise, medications or vomiting to get rid of the food.

(I copied this from betterhelp.com)
6 0
3 years ago
If a 1000-pound capsule weighs only 165 pounds on the moon, how much work is done in propelling this capsule out of the moon's g
Bas_tet [7]

Answer:

  W = 1,307 10⁶ J

Explanation:

Work is the product of force by distance, in this case it is the force of gravitational attraction between the moon (M) and the capsule (m₁)

              F = G m₁ M / r²

              W = ∫ F. dr

              W = G m₁ M ∫ dr / r²

we integrate

             W = G m₁ M (-1 / r)

                 

We evaluate between the limits, lower r = R_ Moon and r = ∞

           W = -G m₁ M (1 /∞ - 1 / R_moon)

            W = G m1 M / r_moon

Body weight is

             W = mg

             m = W / g

The mass is constant, so we can find it with the initial data

For the capsule

            m = 1000/32 = 165 / g_moon

            g_moom = 165 32/1000

            .g_moon = 5.28 ft / s²

I think it is easier to follow the exercise in SI system  

           W_capsule = 1000 pound (1 kg / 2.20 pounds)

           W_capsule = 454 N

           W = m_capsule g

           m_capsule = W / g

           m = 454 /9.8

           m_capsule = 46,327 kg

Let's calculate

          W = 6.67 10⁻¹¹ 46,327   7.36 10²² / 1.74 10⁶

          W = 1,307 10⁶ J

7 0
3 years ago
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