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Zepler [3.9K]
3 years ago
9

The _____ is a coordinating body and generally neither sets policy nor conducts operations. The Joint Task Force commander shoul

d carefully consider the location for easy access for agencies and organizations, force protection and security.
Engineering
2 answers:
denpristay [2]3 years ago
8 0

Answer:

The Civil-Military Operations Center (CMOC).

Explanation:

The Civil-Military Operations Center (CMOC), currently recognized in joint operation, emerges as the most appropriate structure for the planning, coordination, execution, and assessment of civil-military activities. The center should be strategically located to serve its purpose.

nydimaria [60]3 years ago
6 0

Answer:

The Civil-military operations center is a coordinating body

Explanation:

The civil-military operations center is a center that is used while coordinating joint activities between the military and the civilian bodies, this body/center doesn't set policy or conduct operations rather it is meeting place to discuss different operations and policies that have been undertaken by the different bodies meeting up there.

It is usually located in a very secure and accessible area so that in the case of serious crisis whereby the government cannot rule over the country or city from its official stay the CMOC can be used as a place for governing the area temporarily. It is safe haven during combat

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This is a very very difficult one for me, let me get back to you with the proper answer.
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3 years ago
Problem 4.079 SI A rigid tank whose volume is 3 m3, initially containing air at 1 bar, 295 K, is connected by a valve to a large
salantis [7]

Answer:

Q_{cv} = -1007.86kJ

Explanation:

Our values are,

State 1

V=3m^3\\P_1=1bar\\T_1 = 295K

We know moreover for the tables A-15 that

u_1 = 210.49kJ/kg\\h_i = 295.17kJkg

State 2

P_2 =6bar\\T_2 = 296K\\T_f = 320K

For tables we know at T=320K

u_2 = 228.42kJ/kg

We need to use the ideal gas equation to estimate the mass, so

m_1 = \frac{p_1V}{RT_1}

m_1 = \frac{1bar*100kPa/1bar(3m^3)}{0.287kJ/kg.K(295k)}

m_1 = 3.54kg

Using now for the final mass:

m_2 = \frac{p_2V}{RT_2}

m_2 = \frac{1bar*100kPa/6bar(3m^3)}{0.287kJ/kg.K(320k)}

m_2 = 19.59kg

We only need to apply a energy balance equation:

Q_{cv}+m_ih_i = m_2u_2-m_1u_1

Q_{cv}=m_2u_2-m1_u_1-(m_2-m_1)h_i

Q_{cv} = (19.59)(228.42)-(3.54)(210.49)-(19.59-3.54)(295.17)

Q_{cv} = -1007.86kJ

The negative value indidicates heat ransfer from the system

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3 years ago
Determine the constant speed at which the cable at A must be drawn in by the motor in order to hoist the load 6 m in 1.5s
zlopas [31]

Answer:

4m/s

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Power_{motor} } =\frac{Energy }{time}\

We also know that Power = force x velocity      ..................(i)

The force supplied by the motor should be equal to the weight (mg) of the block since we lift the against a force equal to weight of load

=> power = mg x Velocity........(ii)

While hoisting the load at at constant speed only the potential energy of the mass increases

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where

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H = Height to which the load is hoisted  

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m x g x v = \frac{mgh}{t}

thus we get v = H/t

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v = 6/1.5 = 4m/s

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3 years ago
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BARSIC [14]

Answer:

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Explanation:

the answer would be I dont know

6 0
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