Answer:
Please see the attached file for the complete answer.
Explanation:
Answer:
the width of the turning roadway = 15 ft
Explanation:
Given that:
A ramp from an expressway with a design speed(u) = 30 mi/h connects with a local road
Using 0.08 for superelevation(e)
The minimum radius of the curve on the road can be determined by using the expression:
where;
R= radius
= coefficient of friction
From the tables of coefficient of friction for a design speed at 30 mi/h ;
= 0.20
So;
R = 214.29 ft
R ≅ 215 ft
However; given that :
The turning roadway has stabilized shoulders on both sides and will provide for a onelane, one-way operation with no provision for passing a stalled vehicle.
From the tables of "Design widths of pavement for turning roads"
For a One-way operation with no provision for passing a stalled vehicle; this criteria falls under Case 1 operation
Similarly; we are told that the design vehicle is a single-unit truck; so therefore , it falls under traffic condition B.
As such in Case 1 operation that falls under traffic condition B in accordance with the Design widths of pavement for turning roads;
If the radius = 215 ft; the value for the width of the turning roadway for this conditions = 15ft
Hence; the width of the turning roadway = 15 ft
Answer & Explanation:
(a) Frequency of 2Hz is applied to a sampler/zero-order hold combination
The sampling rate is 10Hz
List of all the frequencies present in the output that are less than 50Hz.
Adding:
fs + fm = 10 + 2
= 12 Hz
2fs + fm = 2 * 10 + 2
= 22 Hz
3fs + fm = 3 * 10 + 2
= 32 Hz
4fs + fm = 4 * 10 + 2
= 42 Hz
Subtracting:
fs - fm = 10 - 2
= 8 Hz
2fs - fm = 2 * 10 - 2
= 18 Hz
3fs - fm = 3 * 10 - 2
= 28 Hz
4fs - fm = 4 * 10 - 2
= 38 Hz
5fs - fm = 5 * 10 - 2
= 48 Hz
(b) Frequency of 8Hz is applied to a sampler/zero-order hold combination
The sampling rate is 10Hz
List of all the frequencies present in the output that are less than 50Hz.
Adding:
fs + fm = 10 + 8
= 18 Hz
2fs + fm = 2 * 10 + 8
= 28 Hz
3fs + fm = 3 * 10 + 8
= 38 Hz
Subtracting:
fs - fm = 10 - 8
= 2 Hz
2fs - fm = 2 * 10 - 8
= 12 Hz
3fs - fm = 3 * 10 - 8
= 22 Hz
4fs - fm = 4 * 10 - 8
= 32 Hz
5fs - fm = 5 * 10 - 8
= 42 Hz
Answer:
Option C
A field sparrow is an animal
Explanation:
Collins and Quillian's semantic network approach likened human memory to a computer and the model arranged human knowledge into nodes that were linked in order of hierarchy. Therefore, it would be easier for human knowledge to first link sparrow to sparrow, then field sparrow, then bird and finally as an animal for this case when following the hierarchy as proposed from the model.
The time constant to reach full charge in an RL circuit is 0.05 ms.
Explanation:
To find the time constant,
The time constant for an RL circuit is defined by τ = L/R.
The given data is
L= 5 H
R= 100 ohms
by using the formula,
τ = L/R
= 5/100
= 0.05 ms
τ = 0.05 ms
Thus, the time constant to reach full charge in an RL circuit is 0.05 ms.
