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avanturin [10]
3 years ago
5

In evaluating retrieval rates for category information for a concept, Collins and Quillian's semantic network approach would pre

dict the slowest reaction times for which of the following statements using a sentence verification technique? a. A field sparrow is a bird. b. A field sparrow is a sparrow. c. A field sparrow is an animal. d. A field sparrow is a field sparrow.
Engineering
1 answer:
yan [13]3 years ago
3 0

Answer:

Option C

A field sparrow is an animal

Explanation:

Collins and Quillian's semantic network approach likened human memory to a computer and the model arranged human knowledge into nodes that were linked in order of hierarchy. Therefore, it would be easier for human knowledge to first link sparrow to sparrow, then field sparrow, then bird and finally as an animal for this case when following the hierarchy as proposed from the model.

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The process of using magnetic fields to produce voltage.
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3 years ago
Which alpha-numeric designator, systematically assigned at the time of manufacture, identifies the manufacturer, month, year, lo
Makovka662 [10]

An alpha-numeric designator which is systematically assigned at the time of manufacture, so as to identify the manufacturer, month, year, location, and batch is referred to as lot number.

<h3>What is a product?</h3>

A product can be defined as any physical object (tangible item) that is typically produced by a manufacturer so as to satisfy and meet the demands, needs or wants of every customer. Also, some examples of a product include the following:

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<h3>What is lot number?</h3>

A lot number can be defined as an alpha-numeric designator which is systematically designed and assigned at the time of manufacture, so as to identify the manufacturer, month, year, location, and batch.

Read more on products here: brainly.com/question/14308690

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8 0
2 years ago
LC3 Programming ProblemUse .BLKW to set up an array of 10 values, starting at memory location x4000, as in lab 4.Now programmati
irga5000 [103]

Answer:

Check the explanation

Explanation:

Code

.ORIG x4000

;load index

LD R1, IND

;increment R1

ADD R1, R1, #1

;store it in ind

ST R1, IND

;Loop to fill the remaining array

TEST LD R1, IND

;load 10

LD R2, NUM

;find tw0\'s complement

NOT R2, R2

ADD R2, R2, #1

;(IND-NUM)

ADD R1, R1, R2

;check (IND-NUM)>=0

BRzp GETELEM

;Get array base

LEA R0, ARRAY

;load index

LD R1, IND

;increment index

ADD R0, R0, R1

;store value in array

STR R1, R0,#0

;increment part

INCR

;Increment index

ADD R1, R1, #1

;store it in index

ST R1, IND

;go to test

BR TEST

;get the 6 in R2

;load base address

GETELEM LEA R0, ARRAY

;Set R1=0

AND R1, R1,#0

;Add R1 with 6

ADD R1, R1, #6

;Get the address

ADD R0, R0, R1

;Load the 6th element into R2

LDR R2, R0,#0

;Display array contents

PRINT

;set R1 = 0

AND R1, R1, #0

;Loop

;Get index

TOP ST R1, IND

;Load num

LD R3,NUM

;Find 2\'s complement

NOT R3, R3

ADD R3, R3,#1

;Find (IND-NUM)

ADD R1, R1,R3

;repeat until (IND-NUM)>=0

BRzp DONE

;load array address

LEA R0, ARRAY

;load index

LD R1, IND

;find address

ADD R3, R0, R1

;load value

LDR R1, R3,#0

;load 0x0030

LD R3, HEX

;convert value to hexadecimal

ADD R0, R1, R3

;display number

OUT

;GEt index

LD R1, IND

;increment index

ADD R1, R1, #1

;go to top

BR TOP

;stop

DONE HALT

;declaring variables

;set limit

NUM .FILL 10

;create array

ARRAY .BLKW 10 #0

;variable for index

IND .FILL 0

;hexadecimal value

HEX .FILL x0030

;stop

.END

7 0
3 years ago
Which of the following is the class of ingredient which is the base for most baked items?
Ierofanga [76]

Answer:flour

Explanation:

3 0
3 years ago
Compressed Air In a piston-cylinder device, 10 gr of air is compressed isentropically. The air is initially at 27 °C and 110 kPa
Helen [10]

Answer:

(a) 2.39 MPa (b) 3.03 kJ (c) 3.035 kJ

Explanation:

Solution

Recall that:

A 10 gr of air is compressed isentropically

The initial air is at = 27 °C, 110 kPa

After compression air is at = a450 °C

For air,  R=287 J/kg.K

cv = 716.5 J/kg.K

y = 1.4

Now,

(a) W efind the pressure on [MPa]

Thus,

T₂/T₁ = (p₂/p₁)^r-1/r

=(450 + 273)/27 + 273) =

=(p₂/110) ^0.4/1.4

p₂ becomes  2390.3 kPa

So, p₂ = 2.39 MPa

(b) For the increase in total internal energy, is given below:

ΔU = mCv (T₂ - T₁)

=(10/100) (716.5) (450 -27)

ΔU =3030 J

ΔU =3.03 kJ

(c) The next step is to find the total work needed in kJ

ΔW = mR ( (T₂ - T₁) / k- 1

(10/100) (287) (450 -27)/1.4 -1

ΔW = 3035 J

Hence, the total work required is = 3.035 kJ

4 0
3 years ago
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