Answer:
second one is correct that is right
A uniform thin solid door has height 2.20 m, width .870 m, and mass 23.0 kg. Find its moment of inertia for rotation on its hinges. Is any piece of data unnecessary? So far, I don't understand how to calculate moments of inertia for things like this at all. I can do a system of particles, but when it comes to any ridgid objects, such as this door or rods or cylinders, I don't get it. So basically I have no idea where to even start with this.
so A
Answer:
Pressure, P = 32666.66 Pa
Explanation:
It is given that,
Surface area of foot of Bimaba is 150 cm² or 0.015 m².
Her weight is 50 kg
We need to find the pressure does she exert on the ground, as she stands on her one foot. The force acting per unit area is called pressure. It can be given by :

So, the pressure is 32666.66 Pa.
Answer:
a

b

Explanation:
From the question we are told that
The diameter of the Ferris wheel is 
The period of the Ferris wheel is 
The mass of the passenger is 
The apparent weight of the passenger at the lowest point is mathematically represented as

Where
is the centripetal force on the passenger, which is mathematically represented as

Where
is the angular velocity which is mathematically represented as

substituting values


and r is the radius which is evaluated as 
substituting values


So


W is the weight which is mathematically represented as


So


The apparent weight of the passenger at the highest point is mathematically represented as

substituting values


The additional force needed to bring the car into equilibrium is frictional force.