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prisoha [69]
4 years ago
8

You and your friends find a rope that hangs down 16m from a high tree branch right at the edge of a river. You find that you can

run, grab the rope, swing out over the river, and drop into the water. You run at 2.0 m/s and grab the rope, launching yourself out over the water. How long must you hang on if you want to drop into the water at the greatest possible distance from the edge?
Physics
1 answer:
Harlamova29_29 [7]4 years ago
4 0

Answer:

t = 2\ s

Explanation:

given,

length of the rope = 16 m

speed of the man = 2 m/s

using the formula of time period

T =2 \pi \sqrt{\dfrac{L}{g}}

T =2 \pi \sqrt{\dfrac{16}{9.8}}

T = 8.028\ s

To cover the maximum distance you need to leave the when the rope is shows maximum displacement.

To reach the displacement time to leave the rope is one fourth of the time period.

t = \dfrac{T}{4}

t = \dfrac{8.03}{4}

t = 2\ s

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Answer:

(a) average velocity = 17.6 m/s

(b) when t = 0, v = 0

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(c) after starting from rest, the car will be at rest again in 20 s

Explanation:

Given;

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6t - 0.3t² = 0

t(6 - 0.3t) = 0

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t = 0      or   t = 6 / 0.3

t= 0       or    t =  20 s

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