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Vikentia [17]
3 years ago
15

What do you have to do to become faster at running?

Physics
2 answers:
natali 33 [55]3 years ago
8 0

Answer:

i sa train as much as possible

Explanation:

that's why im a track star

GenaCL600 [577]3 years ago
3 0

Answer: Get stronger. Strength is critical to running fast because the more force you can exert against the ground the faster you can run.

Apply your new strength. Being strong is important for sprinting, but the ability to apply it is even more important. Sprinters move in a horizontal direction.

Take longer steps more quickly. Today, the concept of exerting more force against the ground is very popular for improving speed. ...

Run fast to get fast. Of all the strategies described in this article, this is the most important and often the most overlooked.

Explanation:

You might be interested in
In what direction does an object move when affected by an unbalanced force
gayaneshka [121]

Answer:

An unbalanced force means that there are more than one forces with different directions or magnitudes affecting the object. In this case, the vector addition of the forces should be done. The vector addition will result a net force. The object will move in the direction of the net force.

8 0
3 years ago
The temperature of water in a beaker is 45°C. What does this measurement represent?
Tasya [4]

Answer:

the average kinetic energy of water particles - C.

8 0
3 years ago
If the change in kinetic energy of a tennis ball hit by the racket
Marrrta [24]

Answer: .36 m

Explanation:

5 0
3 years ago
What is the work done when a 400.n force is use to lift a 400.n object 3.5 meters strait up
alexandr1967 [171]

Answer:

i think it's 1400

Explanation:

w = Force x displacement

w = 400 x 3.5

3 0
3 years ago
A particle with mass 1.81*10^-3kg and a charge of 1.22*10^-8C has, at a given instant, a velocity v= (3.0*10^4 m/s)j.
charle [14.2K]

Answer:

a = -0.33 m/s² k^

Direction: negative

Explanation:

From Newton's law of motion, we know that;

F = ma

Now, from magnetic fields, we know that;. F = qVB

Thus;

ma = qVB

Where;

m is mass

a is acceleration

q is charge

V is velocity

B is magnetic field

We are given;

m = 1.81 × 10^(−3) kg

q = 1.22 × 10 ^(−8) C

V = (3.00 × 10⁴ m/s) ȷ^.

B = (1.63T) ı^ + (0.980T) ȷ^

Thus, since we are looking for acceleration, from, ma = qVB; let's make a the subject;

a = qVB/m

a = [(1.22 × 10 ^(−8)) × (3.00 × 10⁴)ȷ^ × ((1.63T) ı^ + (0.980T) ȷ^)]/(1.81 × 10^(−3))

From vector multiplication, ȷ^ × ȷ^ = 0 and ȷ^ × i^ = -k^

Thus;

a = -0.33 m/s² k^

7 0
3 years ago
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