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3 years ago

What do you have to do to become faster at running?

Physics

2 answers:

natali 33 [55]3 years ago

8 0

Answer:

i sa train as much as possible

Explanation:

that's why im a track star

GenaCL600 [577]3 years ago

3 0

Answer: Get stronger. Strength is critical to running fast because the more force you can exert against the ground the faster you can run.

Apply your new strength. Being strong is important for sprinting, but the ability to apply it is even more important. Sprinters move in a horizontal direction.

Take longer steps more quickly. Today, the concept of exerting more force against the ground is very popular for improving speed. ...

Run fast to get fast. Of all the strategies described in this article, this is the most important and often the most overlooked.

Explanation:

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Hey guys! Am I right? Thanks!

worty [1.4K]

Answer:

the correct answer is reduce friction

5 0

3 years ago

A shearing of 50N is applied to an aluminum rod with a length of 10m a cross sectional area of 1.0×10-5 and a shear modulus of 2

slega [8]

Answer:

0.002 m or 2 mm

Explanation:

Given that:

Force, F = 50N

Area = 1 * 10^-5

Length, L = 10m

Shear modulus, = 2.5 * 10^10

Using the relation ;

D = (50 ÷ 1*10^-5) ÷ (2.5 * 10^10 ÷ 10)

D = 5000000 ÷ 2.5 * 10^9

D = 5 * 10^6 ÷ 2.5 * 10^9

D = (5/2.5) * 10^(6-9)

D = 2 * 10^-3

D = 0.002 m

1m = 1000 mm

0.002m = (1000 * 0.002) = 2 mm

7 0

3 years ago

In Hooke’s law, what does k represent?

notsponge [240]

I believe the k value represents the D. Stiffness of the spring.

7 0

3 years ago

Read 2 more answers

Газ виконав роботу 8,5 кДж, отримавши 14,3 кДж теплоти. На скільки змінилася внутрішня енергія газу?

Kitty [74]

Answer:

What is 8,5 after in the game?

Explanation:

7 0

3 years ago

Which velocity graph shows the car moving toward the right (away from the origin) at a steady (constant) velocity?

slega [8]

Explanation:

$\text{Velocity is defined as the average displacement per unit time.}$

$\text{Since the car is moving at a steady velocity, the velocity does not change over time, it shows a horizontal line on the }v-t\text{ graph}$

$\text{Therefore, only option 2,5,8 matches this requirement.}$

$\text{Since the car is moving to the right, which is defined as the positive direction in this question, the velocity (}v\text{) is also positive.}$

$\text{Therefore, only option 5 is correct.}$

6 0

3 years ago