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Rufina [12.5K]
3 years ago
11

In a particular metal, the mobility of the mobile electrons is 0.0033 (m/s)/(N/C). At a particular moment, the electric field ev

erywhere inside a cube of this metal is 0.033 N/C in the x direction. What is the average drift speed of the mobile electrons in the metal at this moment
Physics
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

the average drift speed of the mobile electrons in the metal is 1.089 x 10⁻⁴ m/s.

Explanation:

Given;

mobility of the mobile electrons in the metal, μ = 0.0033 (m/s)/(N/C)

the electric field strength inside the cube of the metal, E = 0.033 N/C

The average drift speed of the mobile electrons in the metal is calculated as;

v = μE

v =  0.0033 (m/s)/(N/C) x 0.033 N/C

v = 1.089 x 10⁻⁴ m/s.

Therefore, the average drift speed of the mobile electrons in the metal is 1.089 x 10⁻⁴ m/s.

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Certain materials can become superconductors under what conditions?
tresset_1 [31]

Option (b) is correct. The certain materials can act as superconductors at a very low temperature.

Explanation:

The Superconductivity of a material is the property of the particular substance to provide no resistance to the path of the current through it. The current does not face any hindrance due to the motion of the other particles inside the conductor.

The superconductivity of a substance leads to the flow of current through the substance or the material without any hindrance. The resistance of a substance is due to the motion of the particles inside it. If all the motion occurring inside the substance are seized, there will be no resistance offered by the conductor.

Therefore, the superconductivity can be defined as the state where all the motions inside the a material are seized. This occurs at a very low temperature. The absolute zero temperature(0\text{ K or }-273^\circ\text{ C}) is regarded as the temperature where there is no motion in any particle.

Thus, Option (b) is correct. The certain materials can act as superconductors at a very low temperature.

Learn More:

1. An electrical shock happens when electric brainly.com/question/3059888

2.  A capacitor with capacitance (c) = 4.50 μf is connected to a 12.0 v battery brainly.com/question/8892837

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Answer Details:

Grade: High School

Subject: Physics

Chapter: Conductivity

Keywords:

material, superconductor, motion, pressure, cold, temperature, substance, material, conditions, superconductivity.

6 0
3 years ago
You are explaining to friends why astronauts feel weightless orbiting in the space shuttle, and they respond that they thought g
bezimeni [28]

Answer:

It's only 1.11 m/s2 weaker at 400 km above surface of Earth

Explanation:

Let Earth radius be 6371 km, or 6371000 m. At 400km above the Earth surface would be 6371 + 400 = 6771 km, or 6771000 m

We can use Newton's gravitational law to calculate difference in gravitational acceleration between point A (Earth surface) and point B (400km above Earth surface):

g = G\frac{M}{r^2}

where G is the gravitational constant, M is the mass of Earth and r is the distance form the center of Earth to the object

\frac{g_B}{g_A} = \frac{GM/r^2_B}{GM/r^2_A}

\frac{g_B}{g_A} = \left(\frac{r_A}{r_B}\right)^2

\frac{g_B}{g_A} = \left(\frac{6371000}{6771000}\right)^2

\frac{g_B}{g_A} = 0.94^2 = 0.885

g_B = 0.885 g_A

So the gravitational acceleration at 400km above surface is only 0.885 the gravitational energy at the surface, or 0.885*9.81 = 8.7 m/s2, a difference of (9.81 - 8.7) = 1.11 m/s2.

6 0
3 years ago
Physics question please help
Molodets [167]

1.4 m/s im in 12th grade did this so this should be right

6 0
3 years ago
Read 2 more answers
12. What type of circuit is the diagram below?<br> series circuit<br> parallel circuit
Dafna1 [17]

Answer:

parallel circuit

Explanation:

An electric circuit can be defined as an interconnection of electrical components which creates a path for the flow of electric charge (electrons) due to a driving voltage.

Generally, an electric circuit consists of electrical components such as resistors, capacitors, battery, transistors, switches, inductors, etc.

Basically, the components of an electric circuit can be connected or arranged in two forms and these includes;

I. Series circuit

II. Parallel circuit: it's an electrical circuit that has the same potential difference (voltage) across its terminals or ends. Thus, its components are connected within the same common points so that only a portion of current flows through each branch.

Hence, the type of circuit that the above diagram above represents is a parallel circuit.

7 0
3 years ago
A helicopter lifts a 81 kg astronaut 19 m vertically from the ocean by means of a cable. The acceleration of the astronaut is g/
nexus9112 [7]

Answer:

a) The work done on the astronaut by the force from the helicopter is W_{h}=16087.68\ J.

b) The work done on the astronaut by the gravitational force is  W_{g}=-15082.2\ J .

Explanation:

We are told that the mass of the astronaut is m=81\ kg, the displacement is \Delta x=19\ m, the acceleration of the astronaut is  |\vec{a}|=\frac{g}{15}  and the acceleration of gravity is g=9.8\ \frac{m}{s^{2}} .

We suppose that in the vertical direction the force from the helicopter F_{h} is upwards and the gravitational force F_{g} is downwards. From the sum of forces we can get the value of F_{h}:

                                               F_{h}-F_{g}=m.a

                                              F_{h}-mg=m.\frac{g}{15}

                                              F_{h}=mg(1+\frac{1}{15})

                              F_{h}=(\frac{16}{15}).81\ kg.\ 9.8\ \frac{m}{s^{2}}\ \Longrightarrow\ F_{h}=846.72\ N

We define work as the product of the force, the displacement of the body and the cosine of the angle \theta between the direction of the force and the displacement of the body:

                                                 W=F.\Delta x.\ cos(\theta)

a) The work done on the astronaut by the force from the helicopter

                                                  W_{h}=F_{h}.\Delta x

                                             W_{h}=846.72\ N.\ 19\ m

                                                  W_{h}=16087.68\ J

b) The work done on the astronaut by the gravitational force

                                                   W_{g}=-F_{g}.\Delta x

                                                    W_{g}=-mg\Delta x

                                            W_{g}=-81\ kg.\ 9.8\ \frac{m}{s^{2}}.\ 19\ m

                                                  W_{g}=-15082.2\ J

                                             

                                                 

                                               

                                       

5 0
3 years ago
Read 2 more answers
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