Answer:
I think the option b
Is the answer
C
Explanation:
after a CCW rotation it would become a waning gibbous, so after a Clockwise rotation it would be a waxing gibbous (opposite)
Gravity,
I hope this correct
7.1 m/s
First, find the time it takes for the fish to reach the water.
Given in the y direction:
Δy = 6.1 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
6.1 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 1.12 s
Next, find the velocity needed to travel 7.9 m in that time.
Given in the x direction:
Δx = 7.9 m
a = 0 m/s²
Find: v₀
Δx = v₀ t + ½ at²
7.9 m = v₀ (1.12 s) + ½ (0 m/s²) (1.12 s)²
v₀ = 7.1 m/s
The momentum of the second object is 125 kg m/s
The momentum of an object is given by
where
m is the mass of the object
v is its velocity
For the object in this problem,
And its mass is m and its velocity is v.
The second object has a mass of and same velocity v, so its momentum is
So, the second object has a momentum that is half of the momentum of the first object, therefore it is:
Learn more about momentum:
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#LearnwithBrainly
Answer: 267 m
2.99x10^8 m/s
———————-
1.12 x 10^6 Hz