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3 years ago

explain why a wrecking ball can destroy a building, but a yo-yo cant. Use the term kinetic energy in your explanation.

2 answers:

7 0

Released weight increases in velocity.

momentum increases as force increases.

momentum= mass x velocity

the wrecking ball has a bigger mass and weight.

the mass of the weight of the wrecking ball is constant, the velocity of the weight as it swings must be increased if momentum is going to be increased.

Goshia [24]3 years ago

3 0

Answer: A wrecking ball can destroy a building because it is larger, and when it hits something, it exerts a lot of <u>kinetic energy.</u>

A yo-yo is too small and does not exert as much kinetic energy because of it's size.

Hope this helps!

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3 years ago

Compute the expected shell-model quadrupole moment of 209Bi () and compare with the experimental value, - 0.37 b

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Answer:

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Explanation:

Quadrupole moment of the nucleon is,

$Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2}$

And also,

$R^{2}=R^{2} _{0}A^{\frac{2}{3} }$

And, $R _{0}=1.2\times 10^{-15}m$

Now,

$Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2} _{0}A^{\frac{2}{3} }$

For Bismuth $j=\frac{9}{2}$ and A is 209.

$Q=-\frac{2\frac{9}{2} -1}{2(\frac{9}{2} +1)}\frac{3}{5}(1.2\times 10^{-15}) ^{2}(209)^{\frac{2}{3} }\\Q=0.628\times 35.28\times 10^{-30} \\Q=22.15\times 10^{-30} m^{2} \\Q=0.2215\times 10^{-28} m^{2} \\Q=0.22 barn$

Therefore, the expected value of quadrupole is 0.22 b which is quite related with experimental value which is 0.37 b

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