Answer:
0.72 Hz minimum frequency
Explanation:
When the damping is negligible,Amplitude is given as

here
= (6.30)/(0.135) = 46.67 N/m kg
= 1.70/(0.135)(0.480) = 26.2 N/m kg
From the above equation , rearranging for ω,

⇒ ω² =46.67 ± 26.2 = 72.87 or 20.47
⇒ ω = 8.53 or 4.52 rad/s
Frequency = f
ω=2 π f
⇒ f = ω / 2π = 8.53 /6.28 or 4.52 / 6.28 = 1.36 Hz or 0.72 Hz
The lower frequency is 0.72 Hz and higher is 1.36 Hz
Answer:
20000 W
Explanation:
Power: This can be defined as the rate at which energy is dissipated or used. The S.I unit of power is Watt(W).
The expression of power is given as,
P = E/t.............................. Equation 1
Where P = power, E = Energy, t = time.
Given: E = 200 J, t = 0.01 s
Substitute into equation 1
P = 200/0.01
P = 20000 W.
Hence the average power = 20000 W
Let us first know the given: Tennis ball has a mass of 0.003 kg, Soccer ball has a mass of 0.43 kg. Having the same velocity at 16 m/s. First the equation for momentum is P=MV P=Momentum M=Mass V=Velocity. Now let us have the solution for the momentum of tennis ball. Pt=0.003 x 16 m/s= ( kg-m/s ) I use the subscript "t" for tennis. Momentum of Soccer ball Ps= 0.43 x 13m/s = ( km-m/s). If we going to compare the momentum of both balls, the heavier object will surely have a greater momentum because it has a larger mass, unless otherwise the tennis ball with a lesser mass will have a greater velocity to be equal or greater than the momentum of a soccer ball.
I suppose it's C. All the other answers are everything but accurate to me
The battery has both a positive side and a negative side. The potential difference will be the potential of the positive end of the battery minus the potential of the negative end, which will result in positive potential, or power. This potential is what gives the electrons the ability to flow from the positive end to the negative end, or to make a current. While the outside of the insulated wire is the insulator, the inside of the wire has copper, which is the conductor of the current. So, this current will go through the copper of the wire (and not the insulator) from the positive side to the negative.