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3 years ago

In an overhead camshaft engine, the lobes make direct contact with the

Physics

2 answers:

luda_lava [24]3 years ago

8 0

The answer would have to be a,value springs

jekas [21]3 years ago

8 0

Answer: B. Rocker arms

Explanation: In an overhead camshaft (OHC) engine,

the camshaft, rocker arms, valve springs, and valves are all

located in the cylinder head. The camshaft is driven off the

crankshaft by using a timing chain. The lobes press directly

up onto rocker arms, and the rocker arms push down on the

valves to open them

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Which statement correctly compares ultraviolet light to visible light? Ultraviolet light has both a lower frequency and longer w

Effectus [21]

The correct statement is

Ultraviolet light has both a higher frequency and a higher radiant energy than visible light.

because ultraviolet light has wavelength smaller than the visible light hence has a greater frequency as compared to visible light. (frequency is inversely related to wavelength. hence smaller the wavelength , greater will be the frequency)

we also know that the radiant energy is directly proportional to the frequency. hence greater the frequency , greater will be the radiant energy.

Since the frequency is greater for ultraviolet light , it radiant energy is also greater

7 0

3 years ago

Read 2 more answers

Manipulate the equation "v=d/t" to find the answers to these problems using

OLEGan [10]

Yo no me voy a ir a la cama a

4 0

3 years ago

During a very quick stop, a car decelerates at 6.8 m/s^2. Assume the forward motion of the car corresponds to a positive directi

geniusboy [140]

Answer:

-24.28571 rad/s²

29.57239 revolutions

3.91176 seconds

52.026478 m

Explanation:

$a_t$ = Tangential acceleration = -6.8 m/s²

r = Radius of wheel = 0.28

$\omega_i$ = Initial angular velocity = 95 rad/s

$\theta$ = Angle of rotation

$\omega_f$ = Final angular velocity

t = Time taken

Angular acceleration is given by

$\alpha=\frac{a_t}{t}\\\Rightarrow \alpha=\frac{-6.8}{0.28}\\\Rightarrow \alpha=-24.28571\ rad/s^2$

The angular acceleration is -24.28571 rad/s²

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-95^2}{2\times -24.28571}\\\Rightarrow \theta=185.80885\ rad=185.80885\times \frac{1}{2\pi}\\\Rightarrow \theta=29.57239\ rev$

The number of revolutions is 29.57239

$\omega_f=\omega_i+\alpha t\\\Rightarrow t=\frac{\omega_f-\omega_i}{\alpha}\\\Rightarrow t=\frac{0-95}{-24.28571}\\\Rightarrow t=3.91176\ s$

The time it takes for the car to stop is 3.91176 seconds

Linear distance

$s=r\theta\\\Rightarrow s=0.28\times 185.80885\\\Rightarrow s=52.026478\ m$

The distance the car travels is 52.026478 m

8 0

3 years ago

A uniform horizontal beam 4.0 m long and weighing 200 N is attached to the wall by a pin connection that allows the beam to rota

wariber [46]

Answer:

The magnitude of the tension in the cable, T is 1,064.315 N

Explanation:

Here we have

Length of beam = 4.0 m

Weight = 200 N

Center of mass of uniform beam = mid-span = 2.0 m

Point of attachment of cable = Beam end = 4.0 m

Angle of cable = 53° with the horizontal

Tension in cable = T

Point at which person stands = 1.50 m from wall

Weight of person = 350 N

Therefore,

Taking moment about the wall, we have

∑Clockwise moments = ∑Anticlockwise moments

T×sin(53) = 350×1.5 + 200×2

T = 850/sin(53) = ‭1,064.315 N.

4 0

2 years ago

What is the name of the force that is a combination of all forces that act on an object?

jarptica [38.1K]

Answer:

If the combination of all the forces acting on an object sums upto be zero, then the net force is known as <u>balanced force.</u>

If the combination of all the forces acting on an object is non-zero, then the net force is said to be <u>unbalanced force. </u>The unbalanced force causes the object change the state of rest or motion.

6 0

3 years ago