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dem82 [27]
2 years ago
14

HELPPP PLEASE!!

Chemistry
1 answer:
Rzqust [24]2 years ago
6 0

Answer:

Herbivores would increase causing producers to decrease.

Explanation:

If the carnivores are gone, herbivores wouldn't get eaten and increase, and more herbivores mean less producers available.

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The volume of a gas is 27.5 mL at 22.0°C and 0.974 atm. What will the volume be at 15.0°C and 0.993 atm? Use Ideal Gas Law (PV =
Scorpion4ik [409]

Answer:

26.3 mL

Explanation:

Step 1:

Obtaining an appropriate gas law from the ideal gas equation.

This is illustrated below:

From the ideal gas equation:

PV = nRT

Divide both side by T

PV/T = nR

At this stage, we'll assume the number of mole (n) to be constant.

Note: R is the gas constant.

PV/T = constant.

We can thus, write the above equation as:

P1V1/T1 = P2V2/T2

The above equation is called the general gas equation.

Step 2:

Data obtained from the question. This includes the following:

Initial volume (V1) = 27.5 mL

Initial temperature (T1) = 22.0°C = 22.0°C + 273 = 295K

Initial pressure (P1) = 0.974 atm.

Final temperature (T2) = 15.0°C = 15.0°C + 273 = 288K

Final pressure (P2) = 0.993 atm

Final volume (V2) =..?

Step 3:

Determination of the final volume of the gas using the general gas equation obtained. This is illustrated below:

P1V1 /T1 = P2V2/T2

0.974 x 27.5/295 = 0.993 x V2/288

Cross multiply to express in linear.

295x0.993xV2 = 0.974x27.5x288

Divide both side by 295 x 0.993

V2 = (0.974x27.5x288)/(295x0.993)

V2 = 26.3 mL

Therefore, the new volume of the gas is 26.3 mL

4 0
3 years ago
What did Asoka do for convicted murderers?
jarptica [38.1K]
Zksjsksjdjxkkdjdkdkdkfkdikdl117283
5 0
2 years ago
In a mixture of 2 ideal gases, A and B, PA = 0.2PB, what is the mole fraction of A?
Alborosie

Answer:

0.1667

Explanation:

Hello,

Dalton's law defines:

y_i=\frac{P_i}{P_T}

A total pressure is:

P_T=P_A+P_B

So, for A (solving for P_A in the previous equation, we get:

y_A=\frac{P_A}{P_A+P_B}

Since P_A=0.2P_B, we obtain:

y_A=\frac{P_A}{P_A+P_A/0.2}\\y_A=\frac{1}{6}\\y_A=0.1667}

Best regards.

7 0
3 years ago
How can Newton's Third Law of Motion be used to explain why it is difficult to walk on a slippery surface, such as ice?
Olenka [21]
E ground pushes you forward. But that interaction is friction. Reduce friction and it doesn't matter how strong your legs are, the surface is incapable of pushing you accordingly. The coefficient of static friction is very low so it is easy to slide your foot rather than push.
6 0
3 years ago
Mrs. Rushing fills a balloon with hydrogen gas to demonstrate its ability to burn. Which combination could she use to produce th
ale4655 [162]

Answer:

Mg and HCI

Explanation:

3 0
3 years ago
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