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Free_Kalibri [48]
3 years ago
10

You no longer feel your clothes against your skin after you have been wearing them for a while. What explains this?

Physics
2 answers:
mariarad [96]3 years ago
6 0
You don't constantly feel your clothes on you because of sensory adaption. So basically your body got used to it.
forsale [732]3 years ago
3 0

Sensory Adaption...........

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1. What is the gravitational force of attraction between two 800 kg spherical objects that are 5 m apart? What would the gravita
Katyanochek1 [597]

Answer:

the force of gravity between them is quadrupled .

Explanation:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.

4 0
3 years ago
Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 403 km above the earth’s sur
BARSIC [14]

Answer:

v_A=7667m/s\\\\v_B=7487m/s

Explanation:

The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

F_g=\frac{GMm}{R^{2} }

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.

Also, we know that the centripetal force of an object describing a circular motion is given by:

F_c=m\frac{v^{2}}{R}

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.

Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So R_A=6774km=6.774*10^6m and R_B=7103km=7.103*10^6m (Since R_{earth}=6371km). Then, we get:

v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s

In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).

7 0
3 years ago
Which symbol is used for an alpha particle? a. β c. γ b. Δ d. α
xenn [34]
It is the very last answer

6 0
3 years ago
Sally has 5 bracelets and decides to wear 3 of them to school. How many ways can she choose 3 bracelets if the order she wears t
Montano1993 [528]

Answer:

60

first choice = 1/5

second choice = 1/4

third choice = 1/3

5*4*3 = 60   the number of choices

7 0
2 years ago
A kite suspended in the sky is flowing back and forth. Which type of friction is being described?
Mice21 [21]

The type of friction of a kite suspended in the sky that is flowing back and forth is fluid friction. The fluid here is the air that helps the kite move back and forth. The kite feels a drag force due to air which acts in the upward direction.

5 0
3 years ago
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