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olga55 [171]
3 years ago
7

State the success of j.j Thompson model theory​

Physics
1 answer:
Arlecino [84]3 years ago
4 0

Explanation:

See this image for answer

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I just need number 2
il63 [147K]

We will apply the conservation of linear momentum to answer this question.

Whenever there is an interaction between any number of objects, the total momentum before is the same as the total momentum after. For simplicity's sake we mostly use this equation to keep track of the momenta of two objects before and after a collision:

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

Note that v₁ and v₁' is the velocity of m₁ before and after the collision.

Let's choose m₁ and v₁ to represent the bullet's mass and velocity.

m₂ and v₂ represents the wood block's mass and velocity.

The bullet and wood will stick together after the collision, so their final velocities will be the same. v₁' = v₂'. We can simplify the equation by replacing these terms with a single term v'

m₁v₁ + m₂v₂ = m₁v' + m₂v'

m₁v₁ + m₂v₂ = (m₁+m₂)v'

Let's assume the wood block is initially at rest, so v₂ is 0. We can use this to further simplify the equation.

m₁v₁ = (m₁+m₂)v'

Here are the given values:

m₁ = 0.005kg

v₁ = 500m/s

m₂ = 5kg

Plug in the values and solve for v'

0.005×500 = (0.005+5)v'

v' = 0.4995m/s

v' ≅ 0.5m/s

4 0
3 years ago
Explain Newton's first law of motion for an object in<br> motion.
Anit [1.1K]

Answer:

bshghhxhgdyxhsygfhtgedhrugrugdjifgu

rolling of a ball uses motion his bushy we I his own shaken his known fish of his jus on

6 0
2 years ago
The spool has a mass of 50 kg and a radius of gyration of ko = 0.280 m. if the 20-kg block a is released from rest, determine th
Rzqust [24]
V₁ = (1/g)₁ = Way₁ = 20(9.81)(0) = 0
V₂ (Vg)₂ = -WAy₂ = -20(9.81)(0.5) = -98.1J
The kinetic energy because the pool rotates about a fixed axis 
W = VA/rA = VA/0.2 5VA
Mass momen of inertila about fixed axis which passes through point 0
I₀ = mko² = 50(0.280)² = 3.92 kg. m²
∴ The kinetic energy of the system is 
T = 1/2 I₀w² + 1/2mAVA²

= 1/2(3.92)(5VA)² + 1/2 (20) VA² = 59VA²
Now that the system is at rest then T₁ = 0
Energy conservation  is
T₁ +V₁ = T₂ + V₂
0+ 0 = 59VA² + (-98.1)
VA = 1.289 m/s
= 1.29 m/s
5 0
3 years ago
4. A 62.0-kg person, standing on the diving board, dives straight down into the water. Just before striking the water, her speed
Alekssandra [29.7K]

To solve this problem it is necessary to apply the concepts related to the Moment. The moment in terms of the Force and the time can be expressed as

\Delta P = F\Delta t

F = Force

\Delta t = Time

At the same time the moment can be expressed in terms of mass and velocity, mathematically it can be given as

P = m \Delta v

Where

m = Mass

\Delta v = Change in velocity

Our values are given as

\Delta t=1.65s

By equating the two equations we can find the Force,

F\Delta t = m\Delta v

F = \frac{m\Delta v}{\Delta t}

F = \frac{62(1.1-5.5)}{1.65}

Therefore, the net average force will be:

F = - 165N

The negative symbol indicates that the direction of the force is upwards.

7 0
3 years ago
2.10-kg box is moving to the right with speed 8.50 m&gt;s on a horizontal, frictionless surface. At t = 0 a horizontal force is
larisa86 [58]

Explanation:

Below is an attachment containing the solution.

8 0
3 years ago
Read 2 more answers
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