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Usimov [2.4K]
3 years ago
10

A worker drops a wrench from the top of a tower 80m tall. What is the velocity when the

Physics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

39.6 m/s

Explanation:

Taking down to be positive:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

Δy = 80 m

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (9.8 m/s²) (80 m)

v = 39.6 m/s

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every action has an equal and opposite reaction

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Three rocks, each of varying mass and volume, are released from a window at the same time. The window is at height h above the g
krek1111 [17]

Under the assumption that the three rocks are dropped from the same height, they will hit the ground at the same speed. The gravity of Earth is virtually the same for any object that is small compared to the size of the Earth. The acceleration will change with the distance from the Earth, but this change is so small for the range of heights we work with (consider the range of heights from sea level to the tip of Mount Everest) that we can take the average value and assume it to be constant. This constant value of acceleration due to Earth's gravity is 9.80665m/s²


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3 years ago
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How long would it take 2.0x10^20 electrons to pass through a point in a conductor if the current was 10.0A?
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6 0
3 years ago
A diagram of a closed circuit with a power source on the left labeled 6 V. There are 3 resistors in parallel, separate paths, co
AfilCa [17]

Answer:

Current: 1.0 Amperes

The minimum current is flowing through path D

Explanation:

We first find the equivalent resistance to the three resistors in parallel ( which is the total resistance of the circuit) via the equation:

\frac{1}{R_e} =\frac{1}{R_B}+\frac{1}{R_C}+\frac{1}{R_D}\\\frac{1}{R_e} =\frac{1}{10}+\frac{1}{20}+\frac{1}{50}=0.17\\R_e=(1/0.17)\Omega\\R_e=5.88 \Omega

with this info, we can estimate the current going through branch A using Ohm's Law, and the information that the power source is 6 V:

V=I*R\\6V=I*5.88\Omega\\I=\frac{6}{5.88} Amp\\I=1.02A

where the current comes in units of Amperes since all other the quantities are given in the SI system, and we can round this answer to 1.0 Amp following the request to round it to the tenth.

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