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Kobotan [32]
3 years ago
5

Vector B~ has x, y, and z components of 2.5, 3,

Physics
1 answer:
brilliants [131]3 years ago
7 0

Answer:

magnitude:

formula: v=√(x)^2 + (y)^2 + (z)^2

√(2.5)^2 +(3)^2 + (7.8)^2

√76.09

=8.7

I hope this helped :)

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The temperature of a black body is 500 and its radiation is of wavelength 600 . If the number of oscillators with energy is 100
stiks02 [169]

Answer: An equation is missing in your question below is the missing equation

a) ≈ 8396

b) 150 nm/k

Explanation:

<u>A) Determine the number of Oscillators in the black body</u>

number of oscillators = 8395

attached below is the detailed solution

<u>b) determine the peak wavelength of the black body </u>

Black body temperature = 20,000 K

applying Wien's law / formula

λmax = b / T  ------ ( 1 )

T = 20,000 K

b = 3 * 10^6 nm

∴  λmax = 150 nm/k

4 0
2 years ago
Two point charges, 1.8 pC and −1.8 pC, are separated by 7 µm. What is the dipole moment of this pair of charges?
Salsk061 [2.6K]

Answer: 12,600,000Cm

Explanation:

From the data's;

Charges(q) = 1.8 PC equal to 1.8 x 10^¹²C

Distance = 7 micrometer, is equal to 0.0000070m

From the equation of electric dipole moment, p= q x d, where q= charge, d=distance and p is the dipole moment.

Then we have 1.8x10^¹² x 0.0000070= 12,600,000Cm

NB: The charges are identical.

3 0
3 years ago
In an electric motor, the rotating coil of wires wrapped around an iron core is a(n)
hram777 [196]
Armature is the correct answer.
9 0
3 years ago
In a certain time period a coil of wire is rotated from one orientation to another with respect to a uniform 0.38-T magnetic fie
juin [17]
<h2>The emf produced is 7.2 V</h2>

Explanation:

When coil is placed in the magnetic field , the flux attached with it can be found by the relation . Flux Ф = the dot product of magnetic field and area of coil .

Thus Ф = B A cosθ

here B is magnetic field strength and A is the area of coil .

The angle θ is the angle between coil and field direction .

When coil rotates , the angle varies . By which the flux varies . The emf is produced in coil due to variation of flux . The relation for this is

The emf produced ξ = - \frac{d\phi}{dt} =  B A sinθ \frac{d\theta}{dt}

Now in the given problem

5 = 0.38 x A x \frac{d\theta}{dt}                            I

Now if the magnetic field is 0.55 T and all the other terms are same , the emf produced

ξ = 0.55 x A x \frac{d\theta}{dt}                              Ii

dividing II by I , we have

\frac{\xi}{5} = \frac{0.55}{0.38} = 1.45

or ξ = 7.2 V

6 0
3 years ago
It is estimated that 1kg of body fat will provide 3.8 * 10^7 J of energy. A 67kg mountain climber decides to climb a mountain 35
xz_007 [3.2K]
During a climb UP the mountain, gravity does NO work on the climber.
Actually, it's more correct to say that gravity does NEGATIVE work
on him.  The climber has to DO the positive work to haul himself up.
  
                     Work = (mass) x (gravity) x (height) .

For the guy in this problem:

                     Work = (67 kg) x (9.8 m/s²) x (3,500 meters)

                             =  2,298,100 joules.

If he eats no candy bars on the way, and completely depends on
his stored body fat for the energy, then he'll burn off

                       (2,298,100 joules) / (3.8 x 10⁷ joules/kg)

                   =          0.06 kg of fat.

That's only about 2.1 ounces.  We KNOW he'll lose more weight than that,
climbing 11,000 feet.  That's because climbing is pretty inefficient. 
In addition to the potential energy you have to give your body weight,
you also have to expend energy breathing, digesting, metabolizing,
and sweating.
4 0
3 years ago
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