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Kobotan [32]
3 years ago
5

Vector B~ has x, y, and z components of 2.5, 3,

Physics
1 answer:
brilliants [131]3 years ago
7 0

Answer:

magnitude:

formula: v=√(x)^2 + (y)^2 + (z)^2

√(2.5)^2 +(3)^2 + (7.8)^2

√76.09

=8.7

I hope this helped :)

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The potential energy (P.E) of X at r is less than P.E at s.

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The speed of Y at i is .greater than that at v.

The kinetic energy (KE) of z at u is less than that at n.

The PE of Y at s is less than the PE of X at c.

The PE of X at c is less than the PE of Z at c.

The PE of X at c is less than the PE of Z at c.

<h3>PE of X at r  and at s</h3>

The potential energy (P.E) of X at r is less than P.E at s due to greater displacement at s.

<h3>TE of Y is .... the TE of X</h3>

The total energy (T.E) of Y is less than total energy (T.E) of X because X has greater displacement from the planet.

<h3>PE of Y at v is .... the PE of Z at c</h3>

The PE of Y at v is greater than the PE of Z at c due to greater displacement at v.

<h3>Speed of Y at i is .... that at u</h3>

The speed of Y at i is .greater than that at v because i is closer to the planet than v.

<h3>KE of Z at u is .... that at n</h3>

The kinetic energy (KE) of z at u is less than that at n because n is closer to the planet and will have greater velocity.

<h3> PE of Y at s is .... the PE of X at c</h3>

The PE of Y at s is less than the PE of X at c, because position c has greater displacement.

<h3>The TE of Z is .... the TE of X</h3>

The TE of Z is greater than the TE of X due to greater displacement of Z from the planet.

<h3>The PE of X at c is .... the PE of Z at c</h3>

The PE of X at c is less than the PE of Z at c due to greater displacement of Z from c.

Learn more about potential energy here: brainly.com/question/1242059

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