Answer:
The boat's acceleration is 4 m/s²
Explanation:
This question seeks to test the knowledge of acceleration and how to calculate acceleration when the speed is provided. Hence, the formula for acceleration would be used here.
Acceleration (m/s²) = speed (in m/s) ÷ time (in seconds)
Acceleration = 80 m/s ÷ 20 secs
Acceleration = 4 m/s² or 4 ms⁻²
The boat's acceleration is 4 m/s²
Answer:
11m
Explanation:
Wavelength of a wave is the distance between successive crests and trough of a wave. It is represented mathematically as the ratio of the speed of the wave to its frequency. It can be expressed as;
Wavelength ¶ = wave speed (v) /frequency (f)
Given the speed of light c = 2.9979 10^8 m/s.
frequency of the radio wave = 27.075 MHz = 27.075×10^6Hz
Wavelength = 2.9979 10^8/27.075×10^6
Wavelength = 0.11×10^2
Wavelength = 11m
Therefore, the wavelength of the electromagnetic wave being used is 11m
Explanation:
Let
= distance traveled while accelerating
= distance traveled while decelerating
The distance traveled while accelerating is given by
We need the velocity of the rocket after 30 seconds and we can calculate it as follows:
This will be the initial velocity when start calculating for the distance it traveled while decelerating.
Solving for 
we get
Therefore, the total distance x is
Answer:
Explanation:
Moment of inertia of the metal rod pivoted in the middle
= M l² / 12
If the spring is compressed by small distance x twisting the rod by angle θ
restoring force by spring
= k x
moment of torque about axis
= k x l /2
= k θ( l /2 )² ( x / .5 l = θ )
=
moment of torque = moment of inertia of rod x angular acceleration
k θ( l /2 )² = M l² / 12 d²θ/dt²
d²θ/dt² = 3 k/M θ
acceleration = ω² θ
ω² = 3 k/M
ω = √ 3 k / M
