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4 years ago

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A crow drops .11 -kg clam onto a rocky beach from a height of 9.8 m. What is the kinetic energy of the clam when it is 5.0 m abo

ve the ground? What is it's speed at that point?

1 answer:

Alchen [17]4 years ago

5 0

Answer:

Kinetic Energy=5.17J

Speed=9.7m/sec

Explanation:

Given the mass of the clam is m=0.11kg

The height from which the rock was thrown is h=9.8m

Given the rock is at 5m above the ground.

The distance travelled by the rock is (s)=9.8-5=4.8m

The initial velocity is u=0m/sec

let the final velocity be v m/sec

We know that the acceleration of the particle is $a=9.8m/sec^{2}$

We know that $v^{2} -u^{2} =2as$

$v^{2} -0^{2} =2\times 9.8\times 4.8$

$v^{2} =94.08$

v=9.7m/sec

Now the kinetic energy= $\frac{1}{2}mv^{2}$

KE= $\frac{1}{2}\times 0.11\times 9.7^{2}$ =5.17J

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Plzzz someone help me!!!!.

Vlad [161]

Answer:

He could re read his answear.

Explanation:

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3 years ago

A 12.0 kg block rests on an inclined plane. The plane makes an angle of 31.0° with the horizontal, and the coefficient of fricti

allochka39001 [22]

Answer:

The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.

Explanation:

Given that,

Mass = 12.0 kg

Angle = 31.0°

Friction coefficient = 0.158

Mass of second block = 38.0 kg

Using formula of frictional force

$f_{\mu} = \mu N$ ....(I)

Where, N = normal force

$N = mg\cos\theta$

Put the value of N into the formula

$N =12\times9.8\times\cos 31^{\circ}$

$N=100.80\ N$

Put the value of N in equation (I)

$f_{mu}=0.158\times100.80$

$f_{mu}=15.9264\ N$

Now, Weight of second block

$W = mg$

$W=38.0\times9.8$

$W=372.4\ N$

The horizontal force is

$F = mg\sintheta$

$F=12\times9.8\times\sin 31^{\circ}$

$F=60.5684\ N$ ....(II)

(I). We need to calculate the acceleration

$a=m_{2}g-\dfrac{f_{\mu}+mg\sin\theta}{m_{1}+m_{2}}$

$a=\dfrac{372.4-(15.9264+60.5684)}{12+38}$

$a=5.92\ m/s^2$

(II). We need to calculate the tension in the rope

$m_{2}g-T=m_{2}a$

$-T=38\times5.92-38\times9.8$

$T=147.44\ N$

Hence, The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.

5 0

4 years ago

An accelerating voltage of 2.47 x 10^3 V is applied to an electron gun, producing a beam of electrons originally traveling horiz

Dmitry [639]

Answer:

6.3445×10⁻¹⁶ m

Explanation:

E = Accelerating voltage = 2.47×10³ V

m = Mass of electron

Distance electron travels = 33.5 cm = 0.335 cm

$E=\frac{mv^2}{2}\\\Rightarrow v=\sqrt{\frac{2E}{m}}\\\Rightarrow v=\sqrt{\frac{2\times 2470\times 1.6\times 10^{-19}}{9.11\times 10^{-31}}}\\\Rightarrow v=29455356.08671\ m/s$

Deflection by Earth's Gravity

$\Delta =\frac {gt^2}{2}$

Now, Time = Distance/Velocity

$\Delta =\frac {g\frac{s^2}{v^2}}{2}\\\Rightarrow \Delta =\frac{9.81\frac{0.335^2}{29455356.08671^2}}{2}\\\Rightarrow \Delta =6.3445\times 10^{-16}\ m$

∴ Magnitude of the deflection on the screen caused by the Earth's gravitational field is 6.3445×10⁻¹⁶ m

3 0

3 years ago

Technician A says that the radiator should always be inspected for leaks and proper flow before installing a rebuilt engine. Tec

Slav-nsk [51]

Answer:

Both the technicians are right so option C is correct

Explanation:

Both the technicians are right so option C is correct

while installing a rebuilt engine, it is necessary to inspect the leaks and proper flow because if there is leak then cooling oil will flow out of the engine which results in engine heating. Secondly flow should be proper otherwise the oil will not reach to all parts and may cause heating of some parts of engine.

If the cooling fan is defective it won't be suck enough heat from engine and it will also cause heating.

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3 years ago

Convert 1 second into solar day.

otez555 [7]

DIVIDE 1 BY 86400 TO CONVERT 1 SECOND INTO SOLAR DAY.

6 0

3 years ago