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serg [7]
4 years ago
9

A crow drops .11 -kg clam onto a rocky beach from a height of 9.8 m. What is the kinetic energy of the clam when it is 5.0 m abo

ve the ground? What is it's speed at that point?
Physics
1 answer:
Alchen [17]4 years ago
5 0

Answer:

Kinetic Energy=5.17J

Speed=9.7m/sec

Explanation:

Given the mass of the clam is m=0.11kg

The height from which the rock was thrown is h=9.8m

Given the rock is at 5m above the ground.

The distance travelled by the rock is (s)=9.8-5=4.8m

The initial velocity is u=0m/sec

let the final velocity be v m/sec

We know that the acceleration of the particle is a=9.8m/sec^{2}

We know that v^{2} -u^{2} =2as

v^{2} -0^{2} =2\times 9.8\times 4.8

v^{2} =94.08

v=9.7m/sec

Now the kinetic energy=\frac{1}{2}mv^{2}

KE=\frac{1}{2}\times 0.11\times 9.7^{2}=5.17J

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ikadub [295]

Answer:

Force = 150 Newton.

Explanation:

Given the following data;

Mass = 60kg

Acceleration = 2.5m/s²

To find the force;

Force = mass * acceleration

Force = 60 * 2.5

Force = 150 Newton.

Therefore, the force required to accelerate this mass is 150 Newton.

7 0
3 years ago
How can a charged object cause charges to move within an uncharged object?
Paraphin [41]
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3 0
3 years ago
Based on Newton’s 3rd Law of motion, if a baseball player hits a ball with the bat, the action force is the impact of the bat ag
kicyunya [14]
The forums is a is equal to f divided by m
6 0
3 years ago
How does the period of a wave change if the frequency increases by a factor of three?
ale4655 [162]

Answer:

Period becomes 1/3 of the original

Explanation:

Period = 1/f      if f becomes 3f   then period becomes 1/3 of the original

3 0
2 years ago
An object is attached to the lower end of a 100-coil spring that is hanging from the ceiling. The spring stretches by 0.150 m. T
dlinn [17]

Answer:

0.125m

Explanation:

Given that:

Length of spring = 100m

Extension, e = 0.250

Recall :

F = ke - - - - (1)

Therefore, if spring is cut into 2 halves :

Then,

k = k1 + K2 ; since k1 and K2 are of equal length

Extension = e'

k = 2k

F = ke'

Then,

F = 2ke' - - - - - (2)

Equate (1) and (2)

ke = 2ke'

e = e'

0.250 = 2e'

0.250 / 2 = e'

e' = 0.125m

8 0
3 years ago
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