4 years ago

The precision of a measuring instrument is based on the fineness of its scale subdivisions.

Chemistry

2 answers:

Liono4ka [1.6K]4 years ago

3 0

The answer is True . The precision of a measuring is based on the fitness of its scale subdivisions

nevsk [136]4 years ago

3 0

Answer is true.......

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$m_{SO_3}=2.31x10^4gSO_3$

Explanation:

Hello!

In this case, since the reaction between sulfur and oxygen is:

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Whereas there is a 1/2:8 mole ratio between oxygen and SO3, and we can compute the produced grams of product as shown below:

$m_{SO_3}=18molO_2*\frac{8molSO_3}{1/2molO_2} *\frac{80.06gSO_3}{1molSO_3} \\\\m_{SO_3}=23,057.3gSO_3=2.31x10^4gSO_3$

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