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postnew [5]
4 years ago
5

The precision of a measuring instrument is based on the fineness of its scale subdivisions.

Chemistry
2 answers:
Liono4ka [1.6K]4 years ago
3 0
The answer is True . The precision of a measuring is based on the fitness of its scale subdivisions
nevsk [136]4 years ago
3 0
Answer is true.......
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Convert 6.71 moles NH3 to number of molecules.
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Answer: There are 40.41 \times 10^{23} molecules present in 6.71 moles of NH_{3}.

Explanation:

Given: Moles of NH_{3} = 6.71 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{22} molecules.

Therefore, molecules present in 6.71 moles are calculated as follows.

Molecules = moles \times 6.022 \times 10^{23}\\= 6.71 \times 6.022 \times 10^{23}\\= 40.41 \times 10^{23}

Thus, we can conclude that there are 40.41 \times 10^{23} molecules present in 6.71 moles of NH_{3}.

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What volume. In liters, of H2O(g) measured at STP is produced by the combustion of 15.63 g of natural gas (CH4) according to the
fomenos

Answer:

V = 43.95 L

Explanation:

Given data:

Mass of CH₄ decomposed = 15.63 g

Volume of H₂O produced at STP = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →       2H₂O  + CO₂

Number of moles of CH₄:

Number of moles = mass/molar mass

Number of moles = 15.63 g/ 16 g/mol

Number of moles = 0.98 mol

Now we will compare the moles of H₂O with CH₄.

                         CH₄              :              H₂O

                           1                 :                2

                        0.98             :            2×0.98 = 1.96 mol

Volume of hydrogen:

PV = nRT

1 atm × V = 1.96 mol × 0.0821 atm.L/mol.K × 273.15 K

V = 43.95atm.L / 1atm

V = 43.95 L

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3 years ago
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