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vova2212 [387]
3 years ago
8

5. You are pulling a rubber sneaker along concrete

Physics
1 answer:
Ainat [17]3 years ago
3 0

Answer:

Fs = 17.66 N

Explanation:

The force of static friction is given by the following formula:

F_s = \mu R = \mu W\\

where,

Fs = The force of static friction = ?

μ = coefficient of static friction = 0.9

W = weight of sneakers = mg

m = mass of sneakers = 2 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

F_s = \mu mg\\F_s = (0.9)(2\ kg)(9.81\ m/s^2)\\

<u>Fs = 17.66 N</u>

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A spring with spring constant 33N/m is attached to the ceiling, and a 4.8-cm-diameter, 1.5kg metal cylinder is attached to its l
mylen [45]

Answer:

0.423m

Explanation:

Conversion to metric unit

d = 4.8 cm = 0.048m

Let water density be \who_w = 1000 kg/m^3

Let gravitational acceleration g = 9.8 m/s2

Let x (m) be the length that the spring is stretched in equilibrium, x is also the length of the cylinder that is submerged in water since originally at a non-stretching position, the cylinder barely touches the water surface.

Now that the system is in equilibrium, the spring force and buoyancy force must equal to the gravity force of the cylinder. We have the following force equation:

F_s + F_b = W

Where F_s = kxN is the spring force, F_b = W_w = m_wg = \rho_w V_s g is the buoyancy force, which equals to the weight W_w of the water displaced by the submerged portion of the cylinder, which is the product of water density \rho_w, submerged volume V_s and gravitational constant g. W = mg is the weight of the metal cylinder.

kx + \rho_w V_s g = mg

The submerged volume would be the product of cross-section area and the submerged length x

V_s = Ax = \pi(d/2)^2x

Plug that into our force equation and we have

kx + \rho_w \pi(d/2)^2x g = mg

x(k + \rho_w g \pi d^2/4) = mg

x = \frac{m}{(k/g) + (\rho_w\pi d^2/4)} = \frac{1.5}{(33/9.8) + (100*\pi * 0.048^2/4)} = 0.423 m

6 0
3 years ago
What is difference between magnetic flux and magnetic flux linkage?​
Anika [276]

Answer:

Magnetic flux has formular: BA while Magnetic flux linkage has formula: NBA

Explanation:

N is number of turns of a coil

B is magnetic flux density across the coil

A is area of coil

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The direction in which heat flows between two bodies depend on their
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PLEASE HELP ME What does a moving charge experience when it is near a magnetic field? static friction gravity a stationary charg
attashe74 [19]

<u><em>A moving charge experiences a force as it moves close to a magnetic field present in a region.</em></u>

Explanation:

A charged particle when moves near a magnetic field is forced to move in a circular path. If there is a straight moving charged particle enters the region of the magnetic field, it's path is changed from straight path to the curved path.

The motion of the charged path inside or near the magnetic field will be a circular path and this circular path is due to the force experienced by the charged particle in the magnetic field.

The force experienced by the a charged particle as it moves near the magnetic field is termed as the Lorentz force. The expression for the Lorentz force experienced by the charged particle in the magnetic field is given by:

\boxed{F_m=Q(\overrightarrow{v}\times\overrightarrow{B})}

Here, F_m is the magnetic force, Q is the amount of charge, \overrightarrow{v} is the velocity vector and \overrightarrow{B} is the magnetic field intensity in the region.

Thus, <u><em>A moving charge experiences a force as it moves close to a magnetic field present in a region.</em></u>

Learn More:

1. Which one is true for the electromagnetic spectrum brainly.com/question/1619496

2. What is the current in resistor R2 brainly.com/question/3051098

3. Average current denisty of a linear wire brainly.com/question/10597501

Answer Details:

Grade: High School

Subject: Physics

Chapter: Electromagnetism

Keywords:

moving, charge, straight, circular, path, magnetic, field, amount, force, velocity, intensity, Lorentz, expression, stationary.

6 0
3 years ago
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