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3 years ago

5. You are pulling a rubber sneaker along concrete

Physics

1 answer:

Ainat [17]3 years ago

3 0

Answer:

Fs = 17.66 N

Explanation:

The force of static friction is given by the following formula:

$F_s = \mu R = \mu W\\$

where,

Fs = The force of static friction = ?

μ = coefficient of static friction = 0.9

W = weight of sneakers = mg

m = mass of sneakers = 2 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$F_s = \mu mg\\F_s = (0.9)(2\ kg)(9.81\ m/s^2)\\$

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3 years ago

Find the intensity of the electromagnetic wave described in each case. (a) an electromagnetic wave with a wavelength of 630 nm a

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Find the intensity of the electromagnetic wave described in each case.

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3 years ago

10. What is the acceleration of a 1000 kg car subject to a 500 N net force?

Simora [160]

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0.5m/s^2

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2 years ago

A convex lens has a focal length of 16.5 cm. Where on the lens axis should an object be placed in order to get a virtual, enlarg

alexandr402 [8]

Answer:

Object should be placed at a distance, u = 7.8 cm

Given:

focal length of convex lens, F = 16.5 cm

magnification, m = 1.90

Solution:

Magnification of lens, m = - $\frac{v}{u}$

where

u = object distance

v = image distance

Now,

1.90 = $\frac{v}{u}$

v = - 1.90u

To calculate the object distance, u by lens maker formula given by:

$\frac{1}{F} = \frac{1}{u}+ \frac{1}{v}$

$\frac{1}{16.5} = \frac{1}{u}+ \frac{1}{- 1.90u}$

$\frac{1}{16.5} = \frac{1.90 - 1}{1.90u}$

$\frac{1}{16.5} = \frac{ 0.90}{1.90u}$

u = 7.8 cm

Object should be placed at a distance of 7.8 cm on the axis of the lens to get virtual and enlarged image.

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3 years ago