Answer:
Explanation:
Given:
Electric Flux = 
Side of sheet = 5cm
Area of the square sheet, A= 5×5 = 25cm²=25×10⁻⁴ m²
Now
the electric flux (Φ) is given as:
where, E = Electric field
or
substituting the values in the above equation, we get
Now the charge density (σ) on a sheet is given as:
where, 
= Permittivity of the free space = 8.85×10⁻¹²
substituting the values in the above equation, we get
Explanation: First fix your units. acceleration is in m/s/s.
T-Mg=Ma
M=348.1+169.2 =517.3 kg
T= 517.3 (9.81+4.11)
I hope this helps
A. When we convert 37.4 mL to ML, the result obtained is 3.74×10¯⁸ ML
B. When we convert 689 km/hr to m/s, the result obtained is 191.39 m/s
C. When we convert 34.5 m² to mm², the result obtained is 3.45×10⁷ mm²
<h3>A. How to convert millimeters (mL) to megaliter (ML)</h3>
- Volume (mL) = 37.4 mL
- Volume (ML) =?
1 mL = 1×10¯⁹ ML
Therefore,
37.4 mL = 37.4 × 1×10¯⁹
37.4 mL = 3.74×10¯⁸ ML
Thus, 37.4 mLis equivalent to 3.74×10¯⁸ ML
<h3>B. How to convert 689 km/hr to m/s</h3>
Conversion scale
3.6 Km/hr = 1 m/s
Therefore,
689 km/hr = 689 / 3.6
689 km/hr = 191.39 m/s
Thus, 689 km/hr is equivalent to 191.39 m/s
<h3>C. How to convert 34.5 m² to mm²</h3>
Conversion scale
1 m² = 1×10⁶ mm²
Therefore,
34.5 m² = 34.5 × 1×10⁶
34.5 m² = 3.45×10⁷ mm²
Thus, 34.5 m² is equivalent to 3.45×10⁷ mm²
Learn more about conversion:
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Answer:
Second drop: 1.04 m
First drop: 1.66 m
Explanation:
Assuming the droplets are not affected by aerodynamic drag.
They are in free fall, affected only by gravity.
I set a frame of reference with the origin at the nozzle and the positive X axis pointing down.
We can use the equation for position under constant acceleration.
X(t) = x0 + v0 * t + 1/2 * a *t^2
x0 = 0
a = 9.81 m/s^2
v0 = 0
Then:
X(t) = 4.9 * t^2
The drop will hit the floor when X(t) = 1.9
1.9 = 4.9 * t^2
t^2 = 1.9 / 4.9
That is the moment when the 4th drop begins falling.
Assuming they fall at constant interval,
Δt = 0.62 / 3 = 0.2 s (approximately)
The second drop will be at:
X2(0.62) = 4.9 * (0.62 - 1*0.2)^2 = 0.86 m
And the third at:
X3(0.62) = 4.9 * (0.62 - 2*0.2)^2 = 0.24 m
The positions are:
1.9 - 0.86 = 1.04 m
1.9 - 0.24 = 1.66 m
above the floor
I say around 40% - 60%
https://www.dmv.ca.gov/portal/dmv/detail/teenweb/more_btn6/traffic/traffic
http://www.teendriversource.org/stats/support_teens/detail/57
http://www.rmiia.org/auto/teens/Teen_Driving_Statistics.asp
(I just corrected the question. Sorry if it is still incorrect.)
