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3 years ago

13

A bowl contains 10 red marbles and 4 green marbles. Carlos randomly draws 3 marbles from the bowl. He does not replace the marbl

e after each draw. What is the probability that he draws 2 red marbles and 1 green marble?

1 answer:

Hunter-Best [27]3 years ago

3 0

3.5% is the correct answer

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You paint a border around the top of the walls in your room. What angle does x need to be to repeat the pattern?

jok3333 [9.3K]

Angle x° and angle 154° are supplementary angles, meaning that they equal 180° when added.

5 0

2 years ago

What are the first three terms of the Arithmetic Sequence a, = 15 - 2(n - 1)?

IgorC [24]

Answer:

C

Step-by-step explanation:

Plug 1, 2, and 3 into n and you'll get 15, 13, and 11 respectively

4 0

2 years ago

You purchase a car worth $25077 and make a down payment of $3560. You intend to repay the balance of the car with month end car

zubka84 [21]

Answer:

value of buyout is $4185.74

Step-by-step explanation:

given data

car worth = $25077

down payment = $3560

monthly payment = $336 = 336 × 6 = $2016 per semi annually

time = 5 year = 10 half yearly

rate = 4.04 %

to find out

value of final buyout

solution

we know here loan amount will be 25077 - 3560 = $21517

and we find present value first by formula that is

present value = $\frac{amount(1+r)^t - 1}{r (1+r)^t}$

put here t = 10 and r = $\frac{4.04}{200}$

so

present value = $\frac{2016(1+\frac{4.04}{200})^10 - 1}{r (1+\frac{4.04}{200})^10}$

present value = 18089.96

so

loan unpaid amount is here

loan unpaid amount = 21517 - 18089.96

loan unpaid amount = $3427.04

so

now we calculate value of buyout

that is express as

amount = principal × $(1+r)^{t}$

amount = 3427.04 × $(1+\frac{4.04}{200})^{10}$

amount = 4185.74

so value of buyout is $4185.74

7 0

3 years ago

What is the sum of the polynomials? 11x^2-5 + x+4

liraira [26]

Answer:

$11x^{2}+x-1$

Step-by-step explanation:

we have

$(11x^{2} -5) +(x+4)$

we know that

The sum of a quadratic equation and a linear equation will be a quadratic equation

so

Combine like terms

$(11x^{2})+(x)+(-5+4)$

$11x^{2}+x-1$

5 0

3 years ago

Read 2 more answers

Please help please these are short answers

atroni [7]

Answer: The answers are given below.

Step-by-step explanation: The calculations are as follows:

(19) Weight of the puppy last week is

$W_\ell=2\dfrac{1}{2}~\textup{lb},$

and weight of the puppy this week is

$W_p=7\dfrac{1}{4}=\dfrac{29}{4}~\textup{lb}.$

Therefore, the weight gained by the puppy is given by

$W_g=W_p-W_\ell=\dfrac{29}{4}-\dfrac{5}{2}=\dfrac{29-10}{4}=\dfrac{19}{4}=4\dfrac{3}{4}~\textup{lb}.$

(20) Time taken in Route 1 = 1 hour 30 minutes.

Time taken in Route 2 = 1 hour 45 minutes.

Time taken in Route 3 = 1 hour 35 minutes.

Time taken in Route 4 = 1 hour 25 minutes.

Since we want to spent the least amount of time on the bus, so we will be taking route 4.

(21) Time taken by Nazia to complete her language arts homework is

$H_\ell=\dfrac{4}{9}~\textup{hr},$

and the time taken by Nazia to complete her Mathematics homework is

$H_m=\dfrac{2}{9}~\textup{hr}.$

Therefore, Nazia takes more time to complete Language Arts homework, by

$H=H_\ell-H_m=\dfrac{4}{9}-\dfrac{2}{9}=\dfrac{2}{9}~\textup{hr}.$

(22) Quantity of Aluminium collected by Maya is

$A_m=\dfrac{4}{20}=0.2~\textup{lb},$

and the quantity of Aluminium collected by her friend Abigail is

$A_a=\dfrac{7}{8}=0.87~\textup{lb}.$

Therefore,

(a) Abigail collected more aluminium

and

(b) Total Aluminium collected by both the girls is

$T=A_m+A_a=\dfrac{4}{20}+\dfrac{7}{8}=\dfrac{8+35}{40}=\dfrac{43}{40}~\textup{lb}.$

(23) Quantity of snow fall last Wednesday is

$S_w=3\dfrac{1}{4}=3.25~\textup{in.},$

and quantity of snowfall on sunday is

$S_s=3\dfrac{4}{5}=3.8~\textup{in.}.$

Therefore, quantity of snowfall was more on Sunday by

$S=S_s-S_w=3\dfrac{4}{5}-3\dfrac{1}{4}=\dfrac{19}{5}-\dfrac{13}{4}=\dfrac{76-65}{20}=\dfrac{11}{20}~\textup{in.}.$

Thus, all the questions are answered.

3 0

3 years ago