Answer:
The force on q₁ due to q₂ is (0.00973i + 0.02798j) N
Explanation:
F₂₁ = ![\frac{K|q_1|q_2|}{r^2}.\frac{r_2_1}{|r_2_1|}](https://tex.z-dn.net/?f=%5Cfrac%7BK%7Cq_1%7Cq_2%7C%7D%7Br%5E2%7D.%5Cfrac%7Br_2_1%7D%7B%7Cr_2_1%7C%7D)
Where;
F₂₁ is the vector force on q₁ due to q₂
K is the coulomb's constant = 8.99 X 10⁹ Nm²/C²
r₂₁ is the unit vector
|r₂₁| is the magnitude of the unit vector
|q₁| is the absolute charge on point charge one
|q₂| is the absolute charge on point charge two
r₂₁ = [(9-5)i +(7.4-(-4))j] = (4i + 11.5j)
|r₂₁| = ![\sqrt{(4^2)+(11.5^2)} = \sqrt{148.25}](https://tex.z-dn.net/?f=%5Csqrt%7B%284%5E2%29%2B%2811.5%5E2%29%7D%20%3D%20%5Csqrt%7B148.25%7D)
(|r₂₁|)² = 148.25
![F_2_1=\frac{K|q_1|q_2|}{r^2}.\frac{r_2_1}{|r_2_1|} = \frac{8.99X10^9(14X10^{-6})(60X10^{-6})}{148.25}.\frac{(4i + 11.5j)}{\sqrt{148.25} }](https://tex.z-dn.net/?f=F_2_1%3D%5Cfrac%7BK%7Cq_1%7Cq_2%7C%7D%7Br%5E2%7D.%5Cfrac%7Br_2_1%7D%7B%7Cr_2_1%7C%7D%20%3D%20%5Cfrac%7B8.99X10%5E9%2814X10%5E%7B-6%7D%29%2860X10%5E%7B-6%7D%29%7D%7B148.25%7D.%5Cfrac%7B%284i%20%2B%2011.5j%29%7D%7B%5Csqrt%7B148.25%7D%20%7D)
= 0.050938(0.19107i + 0.54933j) N
= (0.00973i + 0.02798j) N
Therefore, the force on q₁ due to q₂ is (0.00973i + 0.02798j) N
Answer:
No, the volume don't affect the potential energy.
Explanation:
The volume does not affect the potential energy, as this energy depends on the mass and elevation of the body relative to the reference point. This analysis can be easily seen in the equation expressing potential energy
![E_{p} =m*g*h\\where:\\m=mass[kg]\\g=gravity[m/^2]\\h=elevation[m]](https://tex.z-dn.net/?f=E_%7Bp%7D%20%3Dm%2Ag%2Ah%5C%5Cwhere%3A%5C%5Cm%3Dmass%5Bkg%5D%5C%5Cg%3Dgravity%5Bm%2F%5E2%5D%5C%5Ch%3Delevation%5Bm%5D)
As we know that work done is defined as product of force and displacement in the direction of applied force
so we can say it is
![W = F.d](https://tex.z-dn.net/?f=W%20%3D%20F.d)
or we can say
![W = Fdcos\theta](https://tex.z-dn.net/?f=W%20%3D%20Fdcos%5Ctheta)
so we will have following options
A)Pushing against a locked door
There is no work done in above case as there will be no displacement in that case so work done is ZERO
B) Carrying a box down a corridor
While we move done and carrying a box then work done by gravity on the box while our work done is negative work.
C) Pulling a trailer up a hill
In above case our work done to pull a box up a hill is positive work as we need to work against gravity
D) Suspending a heavy weight with a strong chain
During suspension there is no displacement so there will be no work done in above case
so correct answer will be
<em>Pulling a trailer up a hill</em>