A volleyball is spiked so that its incoming velocity of +2.09 m/s is changed to an outgoing velocity of -24.6 m/s. The mass of t
1 answer:
Answer:
Impulse, J = 9.34 kg-m/s
Explanation:
Given that,
Mass of the volleyball, m = 0.35 kg
Initial velocity, u = +2.09 m/s
Final speed, v = -24.6 m/s
We need to find the magnitude of the impulse that the player applies to the ball. We know that impulse is equal to the change in momentum . So,
So, the magnitude of the impulse that the player applies to the ball is 9.34 kg-m/s.
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Answer:
Option A
Solution:
As per the question:
The distance covered by the woman in the North direction, d = 3000 m
Time taken to travel in North direction, t = 25.0 min = 1500 s
Velocity of woman in the south direction, v = 2.00 m/s
Time taken in the south direction, t' = 60.0 min = 3600 s
Now,
The distance covered in the south direction, d' = vt' =
Now, the total displacement is given by:
D = d' - d = 7200 - 3000 = 4200 m in South
(a) Average velocity of the woman in the whole journey is given by:
≈ 0.824 m/s South