Question

A volleyball is spiked so that its incoming velocity of +2.09 m/s is changed to an outgoing velocity of -24.6 m/s. The mass of the volleyball is 0.350 kg. What is the magnitude of the impulse that the player applies to the ball?

Answer 1

Answer:

Impulse, J = 9.34 kg-m/s

Explanation:

Given that,

Mass of the volleyball, m = 0.35 kg

Initial velocity, u = +2.09 m/s

Final speed, v = -24.6 m/s

We need to find the magnitude of the impulse that the player applies to the ball. We know that impulse is equal to the change in momentum . So,

$J=m(v-u)\\\\J=0.35\times (-24.6-2.09)\\\\J=-9.34\ kg-m/s$

So, the magnitude of the impulse that the player applies to the ball is 9.34 kg-m/s.