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3 years ago

Write an expression that evaluates to true if the value of variable lastName is greater than the string Dexter.

Engineering

1 answer:

gregori [183]3 years ago

4 0

Answer:

lastName.compareTo("Dexter")>0

Explanation:

The expression that evaluates to true if the value of variable lastName is greater than the string Dexter is; lastName.compareTo("Dexter")>0.

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While you are driving you see an animal standing or walking on the side of the road. You should..

STatiana [176]

Take caution, and slow down, it could run out in the middle of the road. Try going around it if possible.

8 0

3 years ago

A pin must be inserted into a collar of the same steel using an expansion fit. The coefficient of thermal expansion of the metal

nirvana33 [79]

Answer:

a) the temperature to which the pin must be cooled for assembly is $T_2 = -101.89^ \ ^0}C$

b) the radial pressure at room temperature after assembly is $P_f = 62.8 \ MPa$

c) the safety factor in the resulting assembly = 6.4

Explanation:

Coefficient of thermal expansion $\alpha = 12.3*10^{-6} \ ^0 C$

Yield strength $\sigma_y$ = 400 MPa

Modulus of elasticity (E) = 209 GPa

Room Temperature $T_1$ = 20°C

outer diameter of the collar $D_o = 95 \ mm$

inner diameter of the collar $D_i = 60 \ mm$

pin diameter $D_p$ = $60.03 \ mm$

Clearance c = 0.06 mm

The temperature to which the pin must be cooled for assembly can be calculated by using the formula:

$(D_i - c )-D_p = \alpha * D_p(T_2-T_1)$

$(60-0.06)-60.03=12.3*10^{-6}*60.03(T_{2}-20^{0}C)$

-0.09 = $7.38369*10^{-4}$ $(T_{2}-20^{0}C)$

-0.09 = $7.38369*10^{-4}T_2$ $\ \ - \ \ 0.01476738$

$-0.09 + 0.01476738$ = $7.38369*10^{-4}T_2$

−0.07523262 = $7.38369*10^{-4}T_2$

$T_2 = \frac{-0.07523262}{7.38369*10^{-4}}$

$T_2 = -101.89^ \ ^0}C$

To determine the radial pressure at room temperature after assembly ;we have:

$P_f = \frac{E * (D_p-D_i)(D_o^2-D_1^2)}{D_i*D_o} \\ \\ \\ P_f = \frac{209*10^9* 0.03(95^2-60^2)}{60*95^2} \\ \\ P_f = 62815789.47 \ Pa \\ \\ P_f = 62.8 \ MPa$

c) the safety factor of the resulting assembly is calculated as:

safety factor = $\frac{Yield \ strength }{walking \ stress}$

safety factor = $\frac{400}{62.8}$

safety factor = 6.4

Thus, the safety factor in the resulting assembly = 6.4

4 0

3 years ago

1. When jump starting a car, make sure it is in __________.

____ [38]

Answer:

Make sure both cars are in park or neutral with the parking brake engaged. This makes sure that all electrical functions (headlights, radios, etc.) are turned off.

8 0

3 years ago

Given that the company "Slate Rock and Gravel" has business locations in Granitetown and Bedrock, suppose that the company has b

kotegsom [21]

Answer:

Check the explanation

Explanation:

As Granitetown requires 5000 IP address and the starting IP address is 192.172.0.0 , we have to perform subnetting using number of hosts required

Number of IP address required by Granitetown=4000

Number of hosts bits =

2n -2= 5000

n=13 (approximately)

Number of hosts bits are 13 therefore subnet prefix =(32-13)=19

We have used 32 because IP address is of 32-bit

Subnet mask corresponding to /19 = 255.255.224.0

Starting IP address (given)= 192.172.0.0

Now to calculate last IP address of the subnet, OR operation will be performed between First IP address of the subnet and !Netmask

First IP address of subnet ( in binary) =

11000000.10101100.00000000.00000000

00000000.00000000.00011111.11111111 (!Netmask)

11000000.10101100.000 11111.11111111 (result)

Converting result into decimal gives IP address 192.172.31.255 which will be the broadcast IP address of the subnet therefore

Last usable IP address = 192.172.31.254

Now, bedrock requires 2000 IP address

Therefore number of host bits are =

2n -2 =2000

n=10 (approximately)

Number of hosts bits required are 10

Therefore Netmask prefix = (32 -10) =22

Now, using the next subnet for bedrock therefore the first IP address of subnet will be 192.172.32.0

Now, similarly calculating last IP address of subnet

First IP address in binary =

11000000.10101100.00100000.00000000

00000000.00000000.00000011.11111111 (!Netmask)

11000000.10101100.00100011.11111111 (result)

Now, result in decimal = 192.172.35.255

Therefore ,

Broadcast address of subnet =192.172.35.255

Last usable IP address =192.172.35.254

8 0

4 years ago

Would you rather be fishing or hunting?

katen-ka-za [31]

Answer:

probs fishing

Explanation:

7 0

3 years ago

Read 2 more answers