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dimaraw [331]
3 years ago
10

3. A drill spins with a frequency of 1200 RPM (revolutions per minute). What is its

Physics
2 answers:
Damm [24]3 years ago
6 0
Your answer is 20
just take 1,200 divided by 60 [second] :)
Nostrana [21]3 years ago
5 0

Frequency = 1200 rev/minute

Frequency = (1200 rev/minute) · (1 minute / 60 seconds)

Frequency = (1200 / 60) (rev - minute / minute - seconds)

<em>Frequency = 20 rev/second</em>

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If a cannonball is fired horizontally it will not go in a straight line why?
goldfiish [28.3K]

Explanation:

A projectile (Cannon ball) is launched at an angle to the horizontal and rises up to a peak while moving horizontally. When it reaches the peak, the projectile starts to fall.

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2 years ago
Does the charge that flows into the capacitor during the charging go all the way through the capacitor and back to the battery,
snow_lady [41]
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4 years ago
How do you increase the rate of dissolving ?
Bogdan [553]
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6 0
4 years ago
Read 2 more answers
Ship A is located 4.1 km north and 2.3 km east of ship B. Ship A has a velocity of 22 km/h toward the south and Ship B has a vel
castortr0y [4]

Answer:

a) x component  = -31.25 km/hr

b) y component = 46.64 km/hr

Explanation:

Given data:

A position is 4km north and 2.5 km east to B

Ship A velocity = 22 km/hr

ship B velocity = 40 km/hr

A velocity wrt to velocity of B

\vec{V_{AB}} =\vec{V_A} - \vec{V_B}

\vec{V_A} = 22 km/hr

\vec{V_B} = 40 cos38\hat{i} + 40sin 38 \hat{j}

                 = 31.52\hat{i} + 24.62 \hat{j}

putting respective value to get velocity of  A with respect to B

\vec{V_{AB}} = -22 \hat {j} - (31.52\hat{i} + 24.62 \hat{j})

\vec{V_{AB}} = -31.52\hat{i} - 46.62\hat{j}

a) x component  = -31.25 km/hr

b) y component = 46.64 km/hr

6 0
3 years ago
A temperature of a 50 kg block increases by 15°C when 337,500 J thermal energy are added to the block. what is the block made of
DENIUS [597]

Answer:

Iron

Explanation:

H = mc∅

Above equation can be used here to find the answer to the question. this equation gives us the relationship between the heat energy supplied to a material and the temperature difference that the material would go through according to its mass.

here H is the Heat energy supplied to the material. m is the mass of the material. c is the specific heat capacity of the material and ∅ is the temperature difference applied to the material. we are given that H= 337,500J , m = 50 kg and ∅ = 15 °C. so from the equation now we can calculate the value of c. after calculating c we can find the material because c is an unique value for a particular material. no two materials have the same c value.

c = 337500/(50*15)

c = 450 J/(kg°C) - Iron (google the heat capacity value to find the answer Iron)

8 0
3 years ago
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