Let w represent the width of the rectangle in cm. Then its length in cm is (3w+9). The perimeter is the sum of two lengths and two widths, so is ...
... 418 = 2(w + (3w+9))
... 209 = 4w +9 . . . . . . divide by 2, collect terms
... 200 = 4w . . . . . . . . subtract 9
... 50 = w . . . . . . . . . . divide by 4
... length = 3w+9 = 3·50 +9 = 159
The dimensions of this piece of land are 159 cm by 50 cm.
Answer:
x = 3
y = 0
Step-by-step explanation:
The method of substitution is when one solves an equation for one of the variables, and then substitutes the expression into the other equation. After doing so, one will solve the other equation for the remaining variable and then backsolve for the first variable.
4x + 2y = 12
x = y + 3
The second equation is already sovled for parameter (x), subttiute this into the other equation,
4(y + 3) + 2y = 12
Distribute,
4y + 12 + 2y = 12
Simplify,
6y + 12 = 12
Inverse operations,
6y + 12 = 12
-12
6y = 0
/6
y = 0
Backsolve for (x), substitute the value of (y) into the equation for (x) and solve,
x = y + 3
x = 0 + 3
x = 3
I think you just add 6 to the output each time the input increases by 1
