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AlekseyPX
3 years ago
3

In which 0.01 M solution is phenolphthalein pink?

Chemistry
1 answer:
8090 [49]3 years ago
3 0
The answer is (2) Ca(OH). The solution that can make phenolphthalein pink is a base. The CH3COOH and HNO3 are acid. CH3OH is a kind of alcohol and is neutral.
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Choose the TRUE statement. A. Laurasia broke up to form Pangaea and Gondwanaland. B. Pangaea broke up to form Laurasia and Gondw
Amanda [17]
B is the correct answer since both Gondwanaland and Laurasia both technically came after pangaea
8 0
3 years ago
Read 2 more answers
How many grams of fosforic acid (H3PO4) are required to prepare 500 mL of a 0.2 M solution?
navik [9.2K]

Answer:

Mass = 9.8 g

Explanation:

Given data:

Molarity of solution = 0.2 M

Volume of solution = 500 mL

Number of grams of phosphoric acid = ?

Solution:

First of all we will convert the volume milliliter to litter.

500 mL × 1 L/1000 mL

0.5 L

Molarity = moles of solute / volume in litter

0.2 M =  number of moles / volume in litter

Number of moles = 0.2 mol/L × 0.5 L

Number of moles = 0.1 mol

Number of grams:

Number of moles = mass/molar mass

Mass = number of moles × molar mass

Mass = 0.1 mol × 98 g/mol

Mass = 9.8 g

7 0
3 years ago
How many liters of hydrogen gas will be produced at STP from the reaction of 5.159 x 1021 atoms of magnesium with 55.23 g of pho
shtirl [24]

Answer:

0.190L of hydrogen may be produced by the reaction.

Explanation:

Our reaction is:

3Mg + 2H₃PO₄ →  Mg₃(PO₄)₂ + 3H₂

We need to determine the limting reactant. Let's find out the moles of each:

5.159×10²¹ atoms . 1 mol / 6.02×10²³ atoms = 0.00857 moles of Mg

55.23 g . 1 mol / 97.97 g = 0.563 moles of acid

2 moles of acid react to 3 moles of Mg

0.563 moles of acid may react to: (0.563 . 3) /2 = 0.8445 moles of Mg

Definetely the limting reactant is Mg.

As ratio is 3:3, 3 moles of Mg can produce 3 moles of hydrogen

Then, 0.00857 moles of Mg must produce 0.00857 moles of H₂

At STP, 1 mol of any gas occupies 22.4L

0.00857 mol . 22.4L / 1mol = 0.190L

3 0
3 years ago
Identify the oxidizing agent and the reducing agent for the following reaction: Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s) Express your answe
Ainat [17]

Answer: oxidizing agent: Cu^{2+}, reducing agent :Zn

Explanation: Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

For the given reaction:

Zn(s)+Cu^{2+}(aq)\rightarrow Zn^{2+}(aq)+Cu(s)

On reactant side:

Oxidation state of zinc = 0

Oxidation state of copper = +2

On product side:

Oxidation state of zinc = +2

Oxidation state of copper = 0

The oxidation state of copper reduces from +2 to 0, it is getting reduced. The substance which itself gets reduced, oxidizes other and is called as oxidizing agent.Thus Cu^{2+} acts as oxidizing agent.

The oxidation state of zinc increases from 0 to +2. Thus, it is getting oxidized and it undergoes oxidation reaction. The substance which itself gets oxidized, reduces other and is called as reducing agent.Thus Zn acts as reducing agent.

3 0
4 years ago
How does the air on a hot day compare with the air on a cold day?
MrMuchimi
Air on a hot day translates to hot air and air on a cold day translates to cold air. The hot air usually have more energy due to particles being more excited by the heat.
7 0
3 years ago
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