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zzz [600]
3 years ago
14

A solid and a liquid are shaken together in a test tube to produce a milky mixture that eventually separates into a clear liquid

and a white solid. which of the following best describes the mixture? solution colloid suspension
Chemistry
2 answers:
neonofarm [45]3 years ago
8 0

The given mixture is best described as \boxed{{\text{suspension}}} .

Further explanation:

1. Solution:

The solution is formed when a solute completely dissolved in a solvent. It is a homogeneous mixture of solute and solvent. For example, salt completely dissolves in water and form homogeneous mixture or a solution.

2. Colloid:

The mixture solute of particles with size between 2 nm to 1000 nm in a solvent is known as the colloid. These particles of solutes can be seen with naked eyes. Also, colloid can be able to show the Tyndall effect which is a scattering of light. In this type of mixture particles of solute are not separated.

3. Suspension:

The mixture solute of particles with size greater than 1000 nm in a solvent is known as the suspension. These particles of solutes can be seen with naked eyes. Also, in this type of mixture particles of solute are settle down due to the gravity.

In the given case white solid shake with liquid which turns the liquid into milky after some time with particles of solid settle down and solution gets clear. Therefore the given mixture is suspension but not solution or colloid.

Learn more:

1.The Characteristics of mixture.:brainly.com/question/1917079

2. Determine the type of reaction occurs on mixing of barium sulfide and sulfuric acid.: brainly.com/question/5464325

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: Solid, liquid, gas, mixture, test tube shaken, milky mixture, separation, colloid, solution, suspension, white solid, size greater than 1000 nm, size between 2 nm to 1000 nm.

Nostrana [21]3 years ago
6 0
This is a suspension

It is a heterogeneous mixture where the solid parts have sedimented on the bottom and are visibly separated from the liquid part of the mix.
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Identify the compound that would have the highest osmotic pressure when dissolved in water. nacl k2so4 mgcl2 fecl3 mgso4
brilliants [131]

The compound that would have the highest osmotic pressure when dissolved in water is FeCl_{3} .

So,  option D is correct one.

The dissociation of one molecule of  FeCl_{3} gives the maximum number of ions when dissolved in water ( 4 ions ) . Osmotic pressure is a colligative property and depends upon number of solute particles present in the solution . The solution having maximum number of solute particles will have maximum number of the osmotic pressure .

All other given molecules gives less number of number of ions when dissolved in water as compare to of  FeCl_{3} .

To learn more about osmotic pressure

brainly.com/question/10046758

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5 0
2 years ago
Complete the dissociation reaction and the corresponding Ka equilibrium expression for each of the following acids in water. (Ty
anastassius [24]

Answer :

(A) The dissociation reaction of HC_2H_3O_2 will be:

HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)

The equilibrium expression :

K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}

(B) The dissociation reaction of Co(H_2O)_6^{3+} will be:

Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)

The equilibrium expression :

K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}

(C) The dissociation reaction of CH_3NH_3^+ will be:

CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)

The equilibrium expression :

K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

(A) The dissociation reaction of HC_2H_3O_2 will be:

HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)

The equilibrium expression of HC_2H_3O_2 will be:

K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}

(B) The dissociation reaction of Co(H_2O)_6^{3+} will be:

Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)

The equilibrium expression of Co(H_2O)_6^{3+} will be:

K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}

(C) The dissociation reaction of CH_3NH_3^+ will be:

CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)

The equilibrium expression of CH_3NH_3^+ will be:

K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}

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Answer:i dont speak english

Explanation:

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