16(2)/74.1=.431
.431x100= 43.1%
Answer:
0.721 g/L
Explanation:
Ideal gas equation ->PV= nRT ; n= mass (m)/ molar mass (M);
densitiy= mass (m)/ volume (V)
PV= (m/M)*RT -> PVM= mRT -> PM/RT= m/V -> PM/RT=d
We need to put in SI units
105 Kpa= 1.04 atm
25°C= 298 K
d= (1.04 atm * 17 g/ mol)/(0.0821 * 298 K) = 0.721 g/L
Answer:
That depends on the size of it
Explanation:
The molar concentration of a sucrose solution prepared by dissolving 350.25 g of sucrose is enough deionized water to yield a final solution volume of 500.00 mL is 2.048 M.
We must first obtain the number of moles of sucrose in the solution as follows;
Number of moles = mass/ molar
Mass of sucrose = 350.25 g
Molar mass of sucrose = 342 g/mol
Number of moles of sucrose= 350.25 g / 342 g/mol
= 1.024 moles
Recall that;
Number of moles = concentration × volume
concentration = Number of moles/volume
volume of solution = 500.00 mL or 0.5 L
concentration = 1.024 moles/0.5 L
concentration = 2.048 M
Learn more: brainly.com/question/13385951
