All categories

3 years ago

1. When there is light, photosynthesis can

Chemistry

2 answers:

Bas_tet [7]3 years ago

8 0

Answer:

Explanation:

ASHA 777 [7]3 years ago

6 0

Answer:

A. occur, in the chloroplast.

Explanation:

Photosynthesis occur in chloroplasts, with the help of sunlight. Where mitochondria help in respiration

You might be interested in

A saturated hydrocarbon is an organic compound which contains hydrogen and carbon joined _____.

Leya [2.2K]

B) with single bonds..... Hope it helps, Have a nice day :)

8 0

3 years ago

Read 2 more answers

A student isolated 7.2 g of 1-bromobutane reacting equimolar amounts of 1-butanol (10 ml) and NaBr (11.1 g) in the presence of s

Alla [95]

Answer: The percent yield of the 1-bromobutane is 48.65 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For NaBr:

Given mass of NaBr = 11.1 g

Molar mass of NaBr = 103 g/mol

Putting values in equation 1, we get:

$\text{Moles of NaBr}=\frac{11.1g}{103g/mol}=0.108mol$

The chemical equation for the reaction of 1-butanol and NaBr is:

$\text{1-butanol + NaBr}\rightarrow \text{1-bromobutane}$

By Stoichiometry of the reaction

1 mole of NaBr produces 1 mole of 1-bromobutane

So, 0.108 moles of NaBr will produce = $\frac{1}{1}\times 0.108=0.108$ moles of 1-bromobutane

Now, calculating the mass of 1-bromobutane from equation 1, we get:

Molar mass of 1-bromobutane = 137 g/mol

Moles of 1-bromobutane = 0.108 moles

Putting values in equation 1, we get:

$0.108mol=\frac{\text{Mass of 1-bromobutane}}{137g/mol}\\\\\text{Mass of 1-bromobutane}=(0.108mol\times 137g/mol)=14.80g$

To calculate the percentage yield of 1-bromobutane, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of 1-bromobutane = 7.2 g

Theoretical yield of 1-bromobutane = 14.80 g

Putting values in above equation, we get:

$\%\text{ yield of 1-bromobutane}=\frac{7.2g}{14.80g}\times 100\\\\\% \text{yield of 1-bromobutane}=48.65\%$

Hence, the percent yield of the 1-bromobutane is 48.65 %

5 0

3 years ago

What factors do not affect nuclear reactions, but do affect chemical reaction

Fudgin [204]

Unlike nuclear reactions, nuclear reactions are not affected by changes in temperature,
pressure, of the presence of catalysts. Also nuclear reactions of given radioisotope cannot be slowed down, speeded up, or stopped.

7 0

3 years ago

Two substances, A and Z, are to be identified. Substance A can not be broken down by a chemical change. Substance Z can be broke

I am Lyosha [343]

The answer is 3). This is because elements are the simplest form of a substance, and cannot be broken down any further. Compounds on the other hand are much more complex than elements and can be broken down INTO elements. For example, Na, sodium, is an element and cannot be broken down further. H2O, water, is a compound and can be broken down into Hydrogen and Oxygen.

4 0

3 years ago

Consider the reaction 2 al + Fe2O3 to 2Fe + Al2O3. If 60.0g of Al is reacted with excess Fe2O3, determine the amount (in moles)

olganol [36]

The amount of Al2O3 in moles= 1.11 moles while in grams = 113.22 grams

calculation

2 Al + Fe2O3 → 2Fe + Al2O3

step 1: find the moles of Al by use of moles= mass/molar mass formula

= 60.0/27= 2.22 moles

Step 2: use the mole ratio to determine the moles of Al2O3.

The mole ratio of Al : Al2O3 is 2: 1 therefore the moles of Al2O3= 2.22/2=1.11 moles

Step 3: finds the mass of Al2O3 by us of mass= moles x molar mass formula.

The molar mass of Al2O3 = (2x27) +( 16 x3) = 102 g/mol

mass is therefore= 102 g/mol x 1.11= 113.22 grams

7 0

3 years ago