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aev [14]
3 years ago
5

7. Small evidence is also called what?

Chemistry
1 answer:
Phoenix [80]3 years ago
6 0

Answer:

minute evidence

hope it is clear

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A. what is atmospheric pressure?
Vanyuwa [196]

Answer:

<em>What is atmospheric pressure? -------> Atmospheric pressure is a force in an area pushed against a surface by the weight of the atmosphere of Earth, a layer of air.</em>

<em>Why does the atmosphere exert pressure? -------> Because gas particles in the air—like particles of all fluids—are constantly moving and bumping into things, so they exert pressure. </em>

<em>What is the value of atmospheric pressure at sea level, in newtons per square centimeter? -------> Atmospheric pressure at sea level is about 10 N/cm2 or 100 kPa or about 10 m of water or about 760 mm of mercury, but varies with the weather, and of course altitude.</em>

<em>I hope this helps and have a great day!</em>

Explanation:

6 0
3 years ago
There is a gas at 780 mm of Hg, in a volume of 5 liters and a temperature of 37 ​ C, the volume is changed to 5.5 liters and the
HACTEHA [7]

Answer:

32.8 C

Explanation:

- Use combined gas law formula and rearrange.

- Hope that helped! Please let me know if you need further explanation.

6 0
4 years ago
Solid lithium chloride decomposes into chlorine gas and solid lithium. Write a balanced equation.
quester [9]
<span>Lithium chloride is LiCl (because the valence of lithium is +1 and the valence of chlorine is -1). So the chemical equation is: Li Cl(s) ----> Li(s) + Cl2 (g). To balance the equation you need to multilply both Li Cl (s) and Li(s) by two, and then you finally get the balanced equation: 2 LiCl ---> 2 Li(s) + Cl2(g). Note that the number 2 to the right of Cl is a subscript.</span>
3 0
3 years ago
12. If a substance has a pH of 3.5, is it<br> acidic or basic?
dolphi86 [110]
The answer is acidic.

pH < 7 = acidic

pH > 7 base
6 0
3 years ago
The radioisotope radon-222 has a half-life of 3.8 days. How much of a 73.9-g sample of radon- (3 222 would be left after approxi
Novay_Z [31]

Answer:

1.115 g

Explanation:

Applying,

R = R'2^{n/t}................... Equation 1

Where R = original sample of radon-222, R' = sample of radon-222 left after decay, n = Total time, t = half-life.

make R' the subject of the equation

R' = R/(2^{n/t})............... Equation 2

From the question,

Given: R = 73.9 g, n = 23 days, t = 3.8 days.

Substitute these values into equation 2

R' = 73.9/(2^{23/3.8})

R' = 73.9/2^{6.05}

R' = 1.115 g

6 0
3 years ago
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