1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
igor_vitrenko [27]
3 years ago
11

What is the frequency of orange light is it has a wavelength of 6.2 x 10^-6 meters?

Physics
2 answers:
Tanya [424]3 years ago
6 0

λ=v/f

λ-wavelength

v-speed

f-frequency

we have the wavelength(6.2 x 10^-6meters) and we use the speed of light which is equal to 3*10^8m/s

6.2*10^-6m=3*10^8m/s/f

f=(3*10^8m/s)/(6.2*10^-6)≈0.48*10^14Hz

serg [7]3 years ago
6 0

Answer:

The frequency of orange light is:

f=\:4.8\:\times \:10^{13} Hz

Step-by-step Explanation:

The relation between frequency and wavelength is

  • v = fλ

Here,

  • v = c = 3×10⁸ m/s
  • wavelength λ = 6.2 x 10⁻⁶ m

Therefore, using the formula

f = c / λ

  =\frac{\left(3\times 10^8\right)}{\left(6.2\:\times 10^{-6}\right)}\:

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

  =\frac{3\times \:10^{8-\left(-6\right)}}{6.2}

   =\frac{10^{14}\times \:3}{6.2}

   =\:4.8\:\times \:10^{13} Hz

Therefore, the frequency of orange light is:

f=\:4.8\:\times \:10^{13}  Hz

You might be interested in
William Gilbert used a terella in an attempt to explain _____.
Alex787 [66]

Answer:

why compasses point towards the north and south poles of the earth.

Explanation:

hope it helps!!

6 0
3 years ago
An airplane weighing 11,000 N climbs to a
Gennadij [26K]

The power in horsepower is 40.1 hp

Explanation:

We start by calculating the work done by the airplane during the climb, which is equal to its change in gravitational potential energy:

W=(mg)\Delta h

where

mg = 11,000 N is the weight of the airplane

\Delta h = 1.6 km = 1600 m is the change in height

Substituting,

W=(11,000)(1600)=17.6\cdot 10^6 J

Now we can calculate the power delivered, which is given by

P=\frac{W}{t}

where

W=17.6\cdot 10^6 J is the work done

t=9.8 min \cdot 60 = 588 s is the time taken

Substituting,

P=\frac{17.6\cdot 10^6 J}{588}=2.99\cdot 10^4 W

Finally, we can convert the power into horsepower (hp), keeping in mind that

1 hp = 746 W

Therefore,

P=\frac{2.99\cdot 10^4}{746}=40.1 hp

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

8 0
3 years ago
A 1.50-V battery supplies 0.414 W of power to a small flashlight. If the battery moves 4.93 1020 electrons between its terminals
slamgirl [31]

Answer:

2.86×10⁻¹⁸ seconds

Explanation:

Applying,

P = VI................ Equation 1

Where P = Power, V = Voltage, I = Current.

make I the subject of the equation

I = P/V................ Equation 2

From the question,

Given: P = 0.414 W, V = 1.50 V

Substitute into equation 2

I = 0.414/1.50

I = 0.276 A

Also,

Q = It............... Equation 3

Where Q = amount of charge, t = time

make t the subject of the equation

t = Q/I.................. Equation 4

From the question,

4.931020 electrons has a charge of (4.931020×1.6020×10⁻¹⁹) coulombs

Q = 7.899×10⁻¹⁹ C

Substitute these value into equation 4

t =  7.899×10⁻¹⁹/0.276

t = 2.86×10⁻¹⁸ seconds

5 0
3 years ago
Nicole throws a ball at 25 m/s at an angle of 60 degrees abound the horizontal. What is the range of the ball?
just olya [345]

Answer:

the range or the ball is 48.81 m

Explanation:

given;

Nicole throws a ball at 25 m/s at an angle of 60 degrees abound the horizontal.

find:

What is the range of the ball?

solution:

let Ф = 25°

Vo = 25 m/s

<u>consider x-motion using time of fight: x = Vox * t</u>

where x = R = range

t =<u> 2 Voy </u>

      g

R =<u> Vo² sin (2Ф)</u>

           g

plugin values into the formula:

R = <u>(25)² sin (2*25) </u>

               9.81

R = 48.81 m

therefore, the range or the ball is 48.81 m

4 0
3 years ago
Read 2 more answers
7. When initially-unpolarized light passes through three polarizing filters, each oriented at 45 degree angles from the precedin
GREYUIT [131]

Answer:

Explanation:

Let the intensity  of unpolarised light be I₀ . After passing through the first polarising filter , the intensity  is I₀ / 2 .

After second filter , the intensity  will be  I₀ / 2 x cos²45 =  I₀ / 4

After third filter , the intensity will be I₀ / 4  x cos²45 = I₀ / 8 .

So,

1 / 8 the of initial light passes through the last filter .

7 0
3 years ago
Other questions:
  • Based on the law of conversation of energy how can we reasonably improve a machines ability to do work?
    5·1 answer
  • Exercise 2.4.6: Suppose you wish to measure the friction a mass of 0.1 kg experiences as it slides along a floor (you wish to fi
    6·1 answer
  • The force of gravity is an inverse square law. this means that, if you double the distance between two large masses, the gravita
    15·1 answer
  • A fan blade rotates with angular velocity given by ωz(t)= γ − β t2, where γ = 4.90 rad/s and β = 0.750 rad/s3 . part a calculate
    10·2 answers
  • Which statement describes a surface wave?
    5·2 answers
  • Spiral galaxy rotation curves are generally fairly flat out to large distances. Suppose that spiral galaxies did not contain dar
    5·1 answer
  • A magnetic field would be produced by a beam of
    7·1 answer
  • FIRST PERSON WILL BE MARKED BRAINLIEST! 50 POINTS!
    5·1 answer
  • Kawas 200 osebanywhes he remembered he had to return some books they​
    14·1 answer
  • An eccentric inventor attempts to levitate a cork ball by wrapping it with foil and placing a large negative charge on the ball
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!