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Genrish500 [490]
3 years ago
5

Write a chemical equation for NH4+(aq) showing how it is an acid or a base according to the Arrhenius definition. Express your a

nswer as a chemical equation. Identify all of the phases in your answer.
Chemistry
1 answer:
Galina-37 [17]3 years ago
8 0

Answer:

NH4+(aq)  → NH3(aq) + H+(aq)

Explanation:

Following arrhenius, an acid can be defined as:

An Arrhenius acid is a substance that, when added to water, increases the concentration of H+ ions in water.

NH4+(aq)  → NH3(aq) + H+(aq)

The ammonium ion acts as a weak acid in aqueous solution, dissociating into ammonia and a hydrogen ion.

An Arrhenius base is a substance that, when added to water, increases the concentration of OH- ions in water.

NH4+(aq) will not dissciate in OH- ions. So it's not a base, but an acid.

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E

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2 years ago
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I believe the answer is C. (must be touching the object)

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Zn +<br> AgCI -<br> ZnCl2 +<br> - Ag<br><br> HELPPP?
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8 0
3 years ago
I need answers to question 1,2,3
sashaice [31]

Answer:

1. 0.125 mole

2. 42.5 g

3. 0.61 mole

Explanation:

1. Determination of the number of mole of NaOH.

Mass of NaOH = 5 g

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mole of NaOH =?

Mole = mass /molar mass

Mole of NaOH = 5/40

Mole NaOH = 0.125 mole

2. Determination of the mass of NH₃.

Mole of NH₃ = 2.5 moles

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mass of NH₃ =?

Mass = mole × molar mass

Mass of NH₃ = 2.5 × 17

Mass of NH₃ = 42.5 g

3. Determination of the number of mole of Ca(NO₃)₂.

Mass of Ca(NO₃)₂ = 100 g

Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]

= 40 + 2[14 + 48]

= 40 + 2[62]

= 40 + 124

= 164 g/mol

Mole of Ca(NO₃)₂ =?

Mole = mass /molar mass

Mole of Ca(NO₃)₂ = 100 / 164

Mole of Ca(NO₃)₂ = 0.61 mole

6 0
2 years ago
What volume of a 1.5 M KOH solution is needed to provide 3.0 moles of KOH?
Leno4ka [110]

2.0 L

Answer:

Solution given:

no. of mole(n)=3.0mole

molarity(M)=1.5M

we have

<u>Volume of a substance is equal to the ratio of its no of mole to its molarity.</u>

By this we get a relation:

Volume=no.of mole/molarity

substituting value

Volume=3.0/1.5=2

The required volume is 2 litre.

3 0
3 years ago
Read 2 more answers
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