Ask question

Ask question

All categories

Genrish500 [490]

3 years ago

5

Write a chemical equation for NH4+(aq) showing how it is an acid or a base according to the Arrhenius definition. Express your a

nswer as a chemical equation. Identify all of the phases in your answer.

1 answer:

Galina-37 [17]3 years ago

8 0

Answer:

NH4+(aq) → NH3(aq) + H+(aq)

Explanation:

Following arrhenius, an acid can be defined as:

An Arrhenius acid is a substance that, when added to water, increases the concentration of H+ ions in water.

NH4+(aq) → NH3(aq) + H+(aq)

The ammonium ion acts as a weak acid in aqueous solution, dissociating into ammonia and a hydrogen ion.

An Arrhenius base is a substance that, when added to water, increases the concentration of OH- ions in water.

NH4+(aq) will not dissciate in OH- ions. So it's not a base, but an acid.

You might be interested in

goldenfox [79]

Answer:

They all contain switches

6 0

2 years ago

Gold is currently trading at very high price. Suppose that gold is selling for around $1860/ounce. How

Ugo [173]

Answer:

The answer is "3.81041978"

Explanation:

$\to 1 \ OZ= 28.349523125 \ grams\\\\$

$=28.349523125\times {1000} \ miligrams\\\\= 28349. 5231 \ miligrams\\$

In 1860 $= 28349.5231 \ miligrams\\$

$\to In \$ \ 1 = \frac{28349.5231}{1860} \ \ miligrams\\$

$= 15.2416791 \ miligrams$

$\ In \ 1 \ quarter = \$ \ 0.25$

$\to \$ \ 0.25 = 15.2416791 \times 0.25 \ miligrams\\$

$= 3.81041978$

3 0

3 years ago

Can you balance 12 blocks on the 3x2 platform

Jobisdone [24]

Yes, it is possible to go do because it would be 2 stacks of 6

3 0

2 years ago

g Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produc

Gala2k [10]

$\text{Ammonia has been studied as an alternative "clean" fuel for internal combustion}$

$\text{engines, since its reaction with oxygen produces only nitrogen and water vapor,}$

$\text{and in the liquid form it is easily transported. An industrial chemist studying this}$

$\text{reaction fills a} \ \mathbf{100 \ L }\ \text{tank with} \ \mathbf{8.6 \ mol} \ \text{of ammonia gas and} \ \mathbf{28 \ mol} \ \ \text{of oxygen gas, }$

$\text{to be} \ \mathbf{2.6\ mol} \ .\ \text{Calculate the concentration equilibrium constant for the combustion of}$

$\text{ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.}$

Answer:

Explanation:

From the correct question above:

The reaction can be represented as:

$\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }$

From the above reaction; the ICE table can be represented as:

$\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }$

I (mol/L) 0.086 0.28 0 0

C -4x -3x +2x +6x

E 0.086 - 4x 0.28 - 3x +2x +6x

At equilibrium;

The water vapor = $\dfrac{2.6 \ mol}{100 \ L} = 6x$

$x = \dfrac{2.6}{100} \times \dfrac{1}{6}$

$x = 0.00433$

$\text{equilibrium constant} ({k_c}) = \dfrac{ [N_2]^2 [H_2O]^6 }{ [[NH_3]^4] [O_2]^3 }$

$\implies \dfrac{(2x)^2 (6x)^6}{(0.086-4x)^4\times (0.28-3x)^3} \\ \\$

Replacing the value of x, we have:

$K_c = \dfrac{4 \times 46,656 \times x^8}{(0.086-4x)^4\times (0.28 -3x)^3} \\ \\ K_c = \dfrac{4 \times 46656 \times (0.00433)^8}{(0.06868)^4(0.26701)^3} \\ \\ K_c = \mathbf{5.4446 \times 10^{-8}}$

$K_c = \mathbf{5.5 \times 10^{-8} \ to \ 2 \ significant \ figures}$

5 0

3 years ago

Consider the reaction below. 2Al2O3 4Al + 3O2 What is the mole ratio of oxygen to aluminum?

DiKsa [7]

The answer is 3/4.

The coefficient next to each reactant represents the amount of moles. The compound for oxygen is O2 and the compound for aluminum is 4. We can see that the number next to O2 is 3 and the number next to aluminum is 4.

8 0

3 years ago

Read 2 more answers