Answer:
0
Explanation:
To calculate, the mass of Carbondioxide is 3.45mg
Then the decomposition of Carbondioxide gives 0 on calculation
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Answer:
The effective nuclear charge for a valence electron in oxygen atom: 
Explanation:
Effective nuclear charge
is the net nuclear charge experienced by the electron in a given atom. It is always less than the actual charge of the nucleus [Z], due to shielding by electrons in the inner shells.
<em>It is equal to the difference between the actual nuclear charge or the atomic number (Z) and the shielding constant (s). </em>

<u>For an oxygen atom</u>-
Electron configuration: (1s²) (2s² 2p⁴)
<em>The atomic number (actual nuclear charge): </em>Z = 8
The shielding constant (s) for a valence electron can be calculated by using the Slater's rules:
⇒ s = 5 × 0.35 + 2 × 0.85 = 1.75 + 1.7 = 3.45
<u><em>Therefore, the effective nuclear charge for a valence electron in oxygen atom is:</em></u>

<u>Therefore, the effective nuclear charge for a valence electron in oxygen atom:</u> 
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Answer:
The correct answer is 2, 0M
Explanation:
We calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter):
250 ml solution----- 0,5 moles of NaCl
1000 ml solution----x= (1000 ml solution x 0,5 moles of NaCl)/250 ml solution
x= 2,0 moles of NaCl --> <em>The solution is 2 M</em>